Mass Continuity Equation Problem

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SUMMARY

The discussion centers on the mass continuity equation in fluid dynamics, specifically the equation dA/A + dv/v + dρ/ρ = 0, which applies to one-dimensional steady flow. The participants confirm that in steady flow, the product of density (ρ), velocity (v), and cross-sectional area (A) remains constant, leading to the conclusion that ρ*v*A = constant. The differentiation of this equation and subsequent division by ρ*v*A is a key step in deriving the mass continuity relationship.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with the mass continuity equation
  • Knowledge of differential calculus
  • Concept of steady flow in fluid mechanics
NEXT STEPS
  • Study the derivation of the mass continuity equation in fluid dynamics
  • Learn about the implications of steady flow on fluid properties
  • Explore applications of the mass continuity equation in engineering problems
  • Investigate the relationship between density, velocity, and area in compressible vs. incompressible flows
USEFUL FOR

Students studying fluid mechanics, engineers working with fluid systems, and anyone interested in the principles of mass conservation in fluid dynamics.

tophat22
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Homework Statement



Question Details:

The question reads:

Show that the equation:

dA/A + dv/v + dρ/ρ = 0

applies to a one-dimensional steady flow. (Here 'one dimensional' means that both the density ρ and seed v = - v . n (vectors) are constant across any cross-sectional area A cutting the flow.)

Please help!

Homework Equations




d/dt ∫V ρ dV + ∫A -ρv⋅n dA = 0

The Attempt at a Solution



I know that the equation they gave us above is the differential equation for ρ*v*A = constant, I just don't know where to go from there.
 
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Hi tophat22! :smile:

In steady flow, mass in = mass out of any surface, so ρ*v*A = constant.

So differentiate ρ*v*A, and divide by ρ*v*A. :wink:
 
I actually ended up getting it before that... thank you though!
 

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