Mass-spring equivalent of microbubbles

  • Thread starter Thread starter enc08
  • Start date Start date
  • Tags Tags
    Equivalent
AI Thread Summary
The discussion focuses on the application of the Gilmore equation to model gas bubbles in a liquid as a mass-spring system. The effective mass of the bubble is determined by the liquid volume it occupies, calculated as m_effective=4πR₀ρ. The effective stiffness, represented by k_effective=12πγP₀R₀, is linked to the compressibility of the gas within the bubble. A detailed explanation is sought regarding how the gas's compressibility contributes to this effective stiffness. The conversation emphasizes the relationship between pressure changes and the bubble's radius during small volume alterations.
enc08
Messages
40
Reaction score
0
Hi,

The Gilmore equation is associated with bubbles in gas. When equated to a mass-spring system, you get the following results.

m_{effective}=4\pi R_{0}\rho
So the effective mass is given by the liquid volume that the bubble occupies. This is easy for me to see as it's effectively the spherical volume multiplied by the liquid's density.

What I don't understand is the following
k_{effective}=12\pi\gamma P_{0}R_{0}
where \gamma is the ratio of specific heats, and P_{0}R_{0} are ambient pressure and radius respectively. My notes say that this means the effective stiffness is provided by the compressibility of the gas. Could someone please explain how this is the case?

Thanks.
 
Physics news on Phys.org
Actually these are gas bubbles in a liquid and not bubbles in gas.
Imagine a spherical bubble of gas of radius Ro and pressure Po and then allow for a small change in volume.
Assume adiabatic transformation and calculate the change in pressure dp due to small change in radius, dr.
Then calculate the force corresponding to the dp on the surface of the sphere.
You'll end up with something that looks like dF = -K dr.
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top