Master Spectroscopy with 13CH3OH: Correct Statements Explained

  • Thread starter Thread starter silver0309
  • Start date Start date
  • Tags Tags
    Spectroscopy
AI Thread Summary
The discussion focuses on the correct statements regarding the spectroscopy of the compound 13CH3OH. The carbon-13 NMR spectrum is expected to show a 1:2:1 triplet due to coupling with protons. The proton NMR spectrum will display a 1:1 doublet and a broad singlet, with the broad singlet resulting from proton exchange among methanol molecules. Alcohols do not exhibit a strong IR absorption around 1750 cm-1; this region is typically associated with carbonyl groups, not alcohols. The mass spectrum of methanol is unlikely to show a peak at mass 15, as this fragment is not characteristic of methanol.
silver0309
Messages
1
Reaction score
0
Indicate those of the following statements that are correct for the compound 13CH3OH
(The 13 in front of C is supposed to indicate carbon-13)

a. The carbon-13 spectrum will be a 1:2:1 triplet.
b. The proton NMR spectrum will be a 1:1 doublet and a broad singlet.
c. The broad singlet in the proton spectrum is due to the exchange of protons among methanol molecules.
d. Because of the oxygen, the IR spectrum will have a strong band around 1750 cm-1.
e. This compound will absorb in the visible region, and will therefore be coloured.
f. The mass spectrum should have a peak at mass 15.

Can someone explain to me which statement(s) are correct?

Thanks
 
Last edited:
Physics news on Phys.org
What do you know about 13-C NMR spectroscopy? Heteronuclear decoupling?
Tell us what you know about 1-H NMR.
What about IR spectroscopy? Do alcohols have a strong absorption at 1750 cm-1?
Any visible chromophores in methanol?
What fragment might have mass = 15? Is it a likely fragment for methanol?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...

Similar threads

Back
Top