Master the Net Change Theorem with Expert Homework Statement Help

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Homework Help Overview

The discussion revolves around the application of the Net Change Theorem in the context of a problem involving the velocity function v(t) = (t - 8)(t + 3). Participants are examining the behavior of this function over a specified interval and how to properly set up the integral for calculating the net change.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correct interpretation of the velocity function and its sign over the interval [6, 12]. There is an exploration of how to express the antiderivative in terms of the absolute value of the velocity function.

Discussion Status

Some participants have provided guidance on the setup of the integral, suggesting a breakdown of the interval based on the critical points of the velocity function. There is an acknowledgment of confusion regarding the setup, but clarity is being sought through collaborative discussion.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may impose specific rules on how to express solutions and interpret functions. The critical points of the velocity function, specifically t = -3 and t = 8, are central to the discussion.

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Homework Statement


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Homework Equations





The Attempt at a Solution


i got -234 for the last part but it should be abs.value so 234.. but it didnt work.
is my work correct?
 
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No. You have v(t) = (t - 8)(t + 3), which is correct, but it's not true that v(t) <= 0 on the interval [6, 11]. Where did the 11 come from? Think about what the factors of v(t) mean. v(t) = 0 only for t = -3 and t = 8. These two numbers divide the number line into three regions, on two of which v(t) > 0 and on one of which v(t) < 0.
 
v(t) > 0 on [-infinity,-3] and [8, infinity]
v(t) < 0 on [-3, 8]

so how do i express the antiderivative?
 
[tex]\int_6^{12} |v(t)|dt~=~\int_6^8 -v(t) dt~+~\int_8^{12} v(t) dt[/tex]

Isn't that what you're trying to do?
 
that what i didnt understand how to set up..
so pretty much you take the number you got for t (which was t= -3, 8)
you pick the one that in the interval [6, 12] (in this case, 8)
and then make it 6 -- > 8 + 8 --> 12
i got it. sweet tnx a lot!
 

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