Another disagreement with course Line integral homework

[1MileCrash]

Homework Statement

http://img39.imageshack.us/img39/6669/wileyplus.png

The field is conservative.

With their description of C, and using the Fundamental Theorem of Calculus for Line Integrals, would you evaluate

f(11/sqrt(2), 11/sqrt(2)) - f(0,0)

or

f(11/sqrt(2), 11/sqrt(2)) - f(11,0)

?


Their description of C, to me, is that we start at the origin and end at (11/sqrt(2), 11/sqrt(2)).

However, their "show solution" shows them doing:

f(11/sqrt(2), 11/sqrt(2)) - f(11,0)


Either I don't understand, or wiley plus has been wrong for the dozenth time. FYI my answer looks so strange because I kept changing it up to get it to accept.

The whole point of path independence is that I don't give a crap about where the circle or whatever starts, the point (11,0) is completely irrelevant!

 

[ehild]

Homework Statement

http://img39.imageshack.us/img39/6669/wileyplus.png

The field is conservative.

With their description of C, and using the Fundamental Theorem of Calculus for Line Integrals, would you evaluate

f(11/sqrt(2), 11/sqrt(2)) - f(0,0)

or

f(11/sqrt(2), 11/sqrt(2)) - f(11,0)

?

It is not that simple. You have to integrate along a line from (0;0) to (11/√2;11/√2).

You can choose the path between (0;0) and (11/√2;11/√2) as you like. One easy choice is along the x-axis from (0;0) to (11/√2;0), then vertically up from (11/√2;0) to (11/√2;11/√2).

Show your work.

ehild

 

[vela]

Wiley Plus is wrong. You're right.

 

[ehild]

1MikeCrash,
yes, the solution in the gray box is correct. I did not realize that it was yours.

ehild