Mastering RC Voltage Calculation for Chopped/Full-Wave Rectified AC Waveforms

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SUMMARY

The discussion focuses on calculating the voltage across a capacitor in an RC circuit supplied by a chopped/full-wave rectified AC waveform. Key insights include the necessity of incorporating bridge diodes in the schematic to prevent capacitor discharge during the lower portions of the waveform. The voltage on the capacitor will be the peak voltage of the input waveform minus the two series diode drops. For accurate calculations, the source impedance and diode drops must be included, and the equations for input current as a function of time should be integrated to determine the capacitor voltage.

PREREQUISITES
  • Understanding of RC circuits and capacitor behavior
  • Knowledge of full-wave rectification and bridge diode configurations
  • Familiarity with differential equations and integration techniques
  • Basic principles of voltage detection circuitry and load impedance
NEXT STEPS
  • Research the impact of bridge diode drops on capacitor voltage in rectified circuits
  • Learn how to derive integrals and differential equations for capacitor charging
  • Explore simplified algebraic equations for capacitor charge-up in various scenarios
  • Investigate experimental methods for measuring capacitor voltage in RC circuits
USEFUL FOR

Electrical engineers, circuit designers, and students working on RC circuit analysis and capacitor voltage calculations in rectified AC applications.

dsa
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I am trying to figure out how to come up with an equation to calculate the voltage
across a capacitor for an RC circuit that is supplied by a chopped / full-wave rectified ac waveform shown below.

The shaded portion is the actual input signal to the RC circuit.


anybody have any ideas ?
 

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Is this a homework/coursework question? If so, I can move this thread to the Homework Help forums.

Welcome to the PF, dsa. If the V(t) waveform is meant to represent the output of a full-wave rectified version of the chopped AC mains, then you need to include the bridge diodes in the schematic, because they will keep the lower portions of the input waveform from discharging the capacitor. If there is no load connected to the output wire that you show, then the voltage on the capacitor will be a peak hold. That is, the voltage will be the max of the input waveform, minus the two series diode drops of the input bridge in conduction. If there is a load connected to the cap, then the cap voltage will likely charge up to the peak voltage, and then droop some between half-cycles based on the load impedance.
 
berkeman said:
Is this a homework/coursework question? If so, I can move this thread to the Homework Help forums.

Welcome to the PF, dsa. If the V(t) waveform is meant to represent the output of a full-wave rectified version of the chopped AC mains, then you need to include the bridge diodes in the schematic, because they will keep the lower portions of the input waveform from discharging the capacitor. If there is no load connected to the output wire that you show, then the voltage on the capacitor will be a peak hold. That is, the voltage will be the max of the input waveform, minus the two series diode drops of the input bridge in conduction. If there is a load connected to the cap, then the cap voltage will likely charge up to the peak voltage, and then droop some between half-cycles based on the load impedance.

Berkeman, this is not a homework question, but part of a design for a circuit I am doing at work.

I understand all of the above mentioned, I was tryin to isolate my problem area.

I am trying to come up with an equation to determine how long it will take to charge the capacitor up to a certain voltage, not the peak. The output wire has voltage detection circuitry with very high impedance so the load can be ignored.
 
Okay, then you will need to include the source impedance of the voltage source and the input full wave bridge diodes in your model, in order to get an accurate calculation. Then set up the equations for the input current as a function of time into the capacitor, and integrate that current over time to calculate the capacitor voltage. Does that make sense?
 
Somewhat...
I do not really care about super exact calculations, I know roughly what the times are from experimentations. I am just trying to come up with a general formula for V(t)
across the cap.
 
dsa said:
Somewhat...
I do not really care about super exact calculations, I know roughly what the times are from experimentations. I am just trying to come up with a general formula for V(t)
across the cap.

For the general equation (including the source impedance and bridge diode drops), you need to use integrals and the differential equation for the current into the capacitor versus the capacitor voltage. Are you comfortable setting up those integral and differential equations?

For simplified cases (-1- Cap charge-up takes less than one quarter cycle, or -2- Cap charge-up takes many cycles), simple algebraic equations can be derived. Are either of the simplifying cases applicable? What are your experimental results so far?
 

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