Math Stellar numbers IB portfolio

Click For Summary

Homework Help Overview

The discussion revolves around finding a general equation for a series of triangular numbers, represented by a data table correlating the term number (n) with its respective value. The subject area is primarily focused on mathematical sequences and series.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore patterns in the triangular numbers and discuss the need for a non-recursive formula. One participant identifies a potential closed form for the nth term and connects it to geometric interpretations.

Discussion Status

Some participants have provided insights into deriving the formula for triangular numbers, while others are seeking clarification on related concepts and tools for visual representation. The discussion includes various interpretations and approaches to the problem.

Contextual Notes

There are mentions of specific software tools for creating diagrams and questions about the scope and limitations of the general statement regarding the triangular numbers.

ihumayun
Messages
12
Reaction score
0

Homework Statement



Its a series of triangles, the data table being
n-#
1-1
2-3
3-6
4-10
5-15

I need a general equation in terms of n.

Homework Equations





The Attempt at a Solution


I can't really find anything. The solution has to be non-recursive, and i can find a bunch of patterns, but all of them rely on the term before and after.
AAAAAAAAAAAAAAAAAH.
 
Physics news on Phys.org
your numbers are 1, 3= 1+ 2, 6= 1+ 2+ 3, 10= 1+ 2+ 3+ 4+ 5, etc.

In particular, the "nth" number is [itex]F(n)= 1+ 2+ 3+ \cdot\cdot\cdot+ (n-2)+ (n-1)+ n[/itex]

To get a "closed form" formula for that note that F(n) is also given by
[itex]F(n)= n+ (n-1)+ (n-2)+ \cdot\cdot\cdot+ 3+ 2+ 1[/itex]

Write those together:
[itex]F(n)= 1+ 2+ 3+ \cdot\cdot\cdot+ (n-2)+ (n-1)+ n[/itex]
[itex]F(n)= n+ (n-1)+(n-2)+ \cdot\cdot\cdot+ 3+ 2+ 1[/itex]

Do you see that if you add those together, each vertical sum is n+1? And that you have n such sums?
 
Ohhhhhohoh.
n(n+1)/2. I get it now. Thank you for your help! I also realized this could be derived by looking at the triangles as half a square, and since the number of dots in a square in n^2, The number in a triangle is (n^2)/2, + n/2 to account for the dots that are cut in half when the square is halved.

Thanks again!
 
hey listen I'm doing the same portfolio. how did u draw the star diagrams?
 
@IB2011 It's tedious work--however if you're willing to put forth the effort, Microsoft Word 2003/2007 will get the job done. Simply click on the "Insert" tab and then click on "Shapes". It took me about two hours to create those meddlesome stars. :/
 
Hey does anyone know the scope and limitations of the general statement?..I don't really get how to explain it . would really appreciate the help !
 
Last edited by a moderator:
@ seth
GeoGebra is a great program to make these figures, mind you it will take a while to create them but they will turn out very nicely.
p.s. The rotate tool is extremely useful.
 
Darwin Monkey said:
@ seth
GeoGebra is a great program to make these figures, mind you it will take a while to create them but they will turn out very nicely.
p.s. The rotate tool is extremely useful.

You're replying to a person that posted nearly a year ago. He's long gone.
 

Similar threads

Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 34 ·
2
Replies
34
Views
7K