Math story problem with fractions that I am stuck on.

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The discussion revolves around solving a math story problem involving fractions of a person's life. The individual spends 1/6 of their life as a boy, 1/8 as a youth, 1/2 as a man, and 15 years as a mature adult. Participants clarify how to set up the equation L/6 + L/8 + L/2 + 15 = L to find the total length of life (L). The correct approach involves combining the fractions and the constant to solve for L accurately. Ultimately, the solution is confirmed to be close to 70 years.
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A guy spends 1/6 of his life as a boy, 1/8 as a youth, 1/2 as a man and 15 years as a mature adult. I got about 70 by trial and error but I need to know exactly how to solve it.
 
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Let the variable L be the length of his life. Add up all of the parts you've got and equate it to L. Now solve for L.
 
I do that and get 15.79. That can't be right.
 
kkaterr said:
I do that and get 15.79. That can't be right.

No, it isn't. Show what you did.
 
(1/6)+(1/8)+(1/2)+15
 
kkaterr said:
(1/6)+(1/8)+(1/2)+15

One sixth of his life is L/6. What's one eighth of his life? What's the total?
 
Going by your logic one eighth would be L/8, I'm not sure what the total is..
 
kkaterr said:
Going by your logic one eighth would be L/8, I'm not sure what the total is..

The total is his whole life. That's L. What's the sum that is equal to L? You are doing fine so far. Write the sum that is equal to L.
 
L/6+L/8+L/2=L
Like that?
 
  • #10
kkaterr said:
L/6+L/8+L/2=L
Like that?

Close. What about the 15? Where does that go?
 
  • #11
L/6+l/8+l/2+15=l
 
  • #12
kkaterr said:
L/6+l/8+l/2+15=l

Yes! Now can you use algebra to solve for L? It is pretty close to 70.
 
  • #13
thank you!
 

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