Mathematically Explain Non-defined Status of s=1

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The discussion centers on the mathematical implications of the equation s=1+(y/x) when both x and y are zero. It is clarified that while s is often stated as 1 under these conditions, this is misleading since y/x becomes undefined when both variables are zero. Instead, if y/x equals 0, it indicates y is zero while x is non-zero. The limits of s vary depending on the path taken towards (0,0); approaching along y=x gives a limit of 2, while y=-x results in a limit of 0. Thus, the value of s is not consistently defined at the origin, highlighting the complexity of limits in multivariable calculus.
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let's assume such equation:

s=1+(y/x)

we usually say that s=1 when both x,y has Zero value

how to explain that mathematically?!
 
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no, we can't say x and y are 0, but we must stipulte y/x = 0. If y and x both = zero, then the value s is undefined since y/x is undefined. And if y/x = 0, then y=0, and x is not equal to 0.
 
electronic engineer said:
let's assume such equation:

s=1+(y/x)

we usually say that s=1 when both x,y has Zero value

how to explain that mathematically?!

I can't explain it because I would never say such a thing! If you approach (0,0) along the line y= x, then s will have a limit of 2. If you approach along the line y= -x, then s will have limit of 0. In fact, given any value a, then approaching (0,0) along the line y= (a-1)x, s has limit a.
 
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