Mathmatical model of a pendulum

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SUMMARY

The discussion focuses on deriving an equation for the amplitude of a pendulum's swing, which decreases exponentially over time. The pendulum is initially released from a maximum distance of 37.4 cm from the wall and reaches a minimum distance of 23.2 cm at 2.8 seconds. The amplitude is calculated as A = (37.4 - 23.2) / 2 = 7.1 cm. The exponential decay of the amplitude is expressed with the equation A(t) = A e^-kt, where k is the decay constant to be determined.

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Homework Statement


Suppose the pendulum string is attached to a point on the ceiling 30 cm from the wall. The weight is moved away from its rest position and released at time t=0. At time t=1.4 sec, it reaches its maximum distance from the wall, 37.4 cm away, and then swings back toward the wall again. At times 2.8 sec, the weight reaches a minimum distance of 23.2 cm form the wall, and then swings away again.
Assuming that the amplitude of the pendulum's swing decreases exponentially with time, find an eqaution expressing the amplitude A in terms of time t.

Homework Equations


A(t)=A e^-kt

The Attempt at a Solution


I tried A(t)= A e^-kt , A= (37.4-23.2)/2=7.1 Don't know what to do next?
 
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bju said:

Homework Statement


Suppose the pendulum string is attached to a point on the ceiling 30 cm from the wall. The weight is moved away from its rest position and released at time t=0. At time t=1.4 sec, it reaches its maximum distance from the wall, 37.4 cm away, and then swings back toward the wall again. At times 2.8 sec, the weight reaches a minimum distance of 23.2 cm form the wall, and then swings away again.
Assuming that the amplitude of the pendulum's swing decreases exponentially with time, find an eqaution expressing the amplitude A in terms of time t.

Homework Equations


A(t)=A e^-kt

The Attempt at a Solution


I tried A(t)= A e^-kt , A= (37.4-23.2)/2=7.1 Don't know what to do next?

Your function does not allow the pendulum bob to oscillate (i.e., swing back and forth).
 

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