Maths Integration Problem HELP

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Homework Help Overview

The discussion revolves around an integration problem involving the expression (2x-1)/√x. Participants are attempting to integrate this expression and are exploring various algebraic manipulations and simplifications to facilitate the integration process.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss splitting the integral into separate terms and simplifying expressions such as x/√x. Questions arise about the integration of specific terms and the manipulation of exponents.

Discussion Status

There is an ongoing exploration of different approaches to the integration problem, with some participants providing guidance on simplification techniques. Multiple interpretations of the integration steps are being discussed, and while some progress has been made, there is no explicit consensus on the final solution.

Contextual Notes

Participants express confusion over specific steps in the integration process and the handling of exponents, indicating a need for clarification on these concepts. There is also mention of a subsequent problem involving a different expression that adds to the complexity of the discussion.

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Maths Integration Problem! HELP!

Homework Statement


ok maths problems is like this:
2.g. integrate (2x-1)/*square root x*

The Attempt at a Solution



ok. i split the equation up so that i am integrating 2x/*root x* - 1/*root x*

the 1/root x integrates to - 2x^(1/2) and the constant is present (+c)

but i cannot seem to integrate the (2x)/(x^(1/2))
the answer is (4/3)x^(3/2)... but i can't seem to get it... even working backwards.
 
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Can you simplify [tex]\frac{x}{\sqrt{x}}[/tex] ?
 
take the two out the front of the integral sign and then multiply?
 
ok. i don't get where the x^(3/2) comes from.
[tex]\frac{x}{\sqrt{x}}[/tex]
becomes x.x^(-1/2)... then we add the powers?
= x^(1/2)?
 
Yes, correct. Can you integrate now?
 
Yes, correct. Can you integrate now?
 
x^(1/2) becomes (2/3)x^3/2) then multiplying in the two becomes...

(4/3)x^(3/2) which is correct yeh?

cool :D



ok another one. (1-4x)/(x*root*x)... i can't do the (4x)/(x^(3/2))
 
[tex]4 \cdot \frac{x}{x^{1.5}}= 4 \cdot x^{-1/2}[/tex]
 
damn it. lol. how stupid of me. missed the cancelling there totally. ah! no wonder i could do the rest of the chapter *shakes head*
 

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