Matrix, Prove of matrix theorem

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Homework Help Overview

The discussion revolves around proving two properties of nonsingular matrices: the transpose of a product and the inverse of a product. Participants are exploring the mathematical properties and relationships of matrices in linear algebra.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method of considering specific elements of matrices to prove the transpose property. There is a question about whether the same approach applies to the inverse property. Some participants express confusion about the teacher's requirement to avoid using specific examples or random matrices in the proof.

Discussion Status

The discussion is active, with some participants offering suggestions on how to approach the proofs. There is a recognition of the need to prove the statements for all nonsingular matrices rather than for specific examples. Multiple lines of reasoning are being explored, particularly regarding the application of matrix properties.

Contextual Notes

Participants are constrained by the requirement to avoid creating random matrices for proofs, which has led to questions about the validity of their approaches. The discussion reflects an ongoing exploration of the definitions and properties of matrix operations.

nekteo
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prove that if ABC are nonsingular matrices,
A) (AB)[tex]^{T}[/tex] = B[tex]^{T}[/tex]A[tex]^{T}[/tex]
B) (ABC)[tex]^{-1}[/tex] = C[tex]^{-1}[/tex]B[tex]^{-1}[/tex]A[tex]^{-1}[/tex]

I attempted to solve it by creating a random matrices by my self and solved it, however, my teacher demand an answer without "creating" a new matrices by our self...
 
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Try considering the ijth element of the matrix. That is, for the first one, consider [itex](AB)^T_{ij}[/itex] and expand.
 
o! i got the 1st question... Thx!
is the 2nd ques also using the same method?

Cheers!
Kenneth
 
nekteo said:
prove that if ABC are nonsingular matrices,
A) (AB)[tex]^{T}[/tex] = B[tex]^{T}[/tex]A[tex]^{T}[/tex]
B) (ABC)[tex]^{-1}[/tex] = C[tex]^{-1}[/tex]B[tex]^{-1}[/tex]A[tex]^{-1}[/tex]

I attempted to solve it by creating a random matrices by my self and solved it, however, my teacher demand an answer without "creating" a new matrices by our self...
Do you understand what your teacher was saying? If you "create a random matrix" and do the calculations for that matrix, then you have proved the statement is true for that matrix. You are asked to prove it is true for any matrix.
 
For the 2nd one let D=(ABC)[tex]^{-1}[/tex] and then go from there
mutilyply by ABC

ABCD=(ABC)[tex]^{-1}[/tex](ABC)
ABCD=I
then proceed to multiply by A[tex]^{-1}[/tex] and so forth

for the first one, I think you need to use the property that if A is a mxn matrix and B is a nxs matrix then AB is mxs matrix..then you need to say what kind of matrix would A[tex]^{T}[/tex] would be.(nxm)
 
Last edited:

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