Max Ball Height: No Mass Needed

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When a ball is thrown directly upward with an initial velocity of 10.0 m/s, its maximum height can be calculated using energy conservation principles, specifically that kinetic energy equals gravitational potential energy. The mass of the ball cancels out in the equations, demonstrating that the maximum height is independent of mass, as gravity accelerates all objects equally in a vacuum. The calculations show that the maximum height reached is approximately 5.1 meters. The discussion emphasizes that, in the absence of air resistance, only gravity acts on the ball after it is released. Understanding this principle clarifies why mass is not needed to determine the maximum height.
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Homework Statement


you throw a ball directly upward, giving it an initial velocity of 10.0 m/s. neglecting friction, what would be the maximum height of the ball? (explain why you do not need to know the mass of the ball)



Homework Equations


now the problem itself i understand.

we need Eg=mgh, Ek=1/2mv^2



The Attempt at a Solution


Ek=Eg
1/2mv^2 = mgh
1/2v^2 = gh
1/2(10.0)^2 = 9.81h
50/9.81 = h
h = 5.1m

i understand that we do not have mass and so it must cancel out, but i am confused as to why we do not need to know the mass?
 
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What falls faster a feather or a cannon ball? (this problem assumes 0 resistance)
 
neglecting air friction, neither..
meaning mass doesn't matter
 
So you're saying that gravity accelerates all masses in an equal manner. This is correct. What is the one force acting upon the ball after you release it?
 
only gravity (in this instance because it says to neglect friction)
 
Yes, do you understand now why you don't need to know the mass of the ball?
 
i understand.
thank you
 
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