Max Capacity Trapezoid Trough: Optimization Problem Q

  • Thread starter Thread starter griffon
  • Start date Start date
  • Tags Tags
    Optimization
griffon
Messages
3
Reaction score
0
Q: A trough is to be made from three planks, each 12 in. wide. If the cross section has the shape of a trapezoid, how far apart should the tops of the sides be placed to give the trough maximum carrying capacity?

OK the area of a trapezoid is
A=2bh
I know that much, but I've been struggling with this one, off and on, for about two days. I just don't know where to start. I'm not looking for an answer, just a starting point please. :confused:
 
Physics news on Phys.org
The area of a trapezoid is,

A = ½(b1 + b2)*h

where b1 and b2 are the lengths of the parallel sides and h is the perpindicular distance between them.

You want to maximise this area, so find a relation between h and (b1 and b2) using the angle the side plank is at.

Then A is a function of the angle. Maximise A wrt the angle.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
3
Views
2K
Replies
6
Views
9K
Replies
1
Views
2K
Replies
1
Views
14K
Replies
8
Views
4K
Back
Top