1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Max height of projectile using energy conservation

  1. Apr 3, 2008 #1
    1. The problem statement, all variables and given/known data

    find max height of a projectile travelling at 40 m/s 60 degrees from the horizontal using conservation of energy

    2. Relevant equations
    KEi + PEi = KEf + PEf???

    3. The attempt at a solution

    couldnt attempt. (I know I can't be given the answer, but even just the proper equation would be handy, thanks!)
    Last edited: Apr 3, 2008
  2. jcsd
  3. Apr 3, 2008 #2


    User Avatar
    Science Advisor
    Homework Helper

    Split the initial velocity v into x and y component, vx and vy. At launch the KE is (1/2)*m*v^2, at max height, it only has a vx component, so KE=(1/2)*m*(vx)^2. Set the KE difference equal to the PE difference m*g*h and solve for height h.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook