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Max height of projectile using energy conservation

  1. Apr 3, 2008 #1
    1. The problem statement, all variables and given/known data

    find max height of a projectile travelling at 40 m/s 60 degrees from the horizontal using conservation of energy

    2. Relevant equations
    KEi + PEi = KEf + PEf???


    3. The attempt at a solution

    couldnt attempt. (I know I can't be given the answer, but even just the proper equation would be handy, thanks!)
     
    Last edited: Apr 3, 2008
  2. jcsd
  3. Apr 3, 2008 #2

    Dick

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    Science Advisor
    Homework Helper

    Split the initial velocity v into x and y component, vx and vy. At launch the KE is (1/2)*m*v^2, at max height, it only has a vx component, so KE=(1/2)*m*(vx)^2. Set the KE difference equal to the PE difference m*g*h and solve for height h.
     
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