Max height of projectile using energy conservation

  • #1

Homework Statement



find max height of a projectile travelling at 40 m/s 60 degrees from the horizontal using conservation of energy

Homework Equations


KEi + PEi = KEf + PEf???


The Attempt at a Solution



couldnt attempt. (I know I can't be given the answer, but even just the proper equation would be handy, thanks!)
 
Last edited:

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
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Split the initial velocity v into x and y component, vx and vy. At launch the KE is (1/2)*m*v^2, at max height, it only has a vx component, so KE=(1/2)*m*(vx)^2. Set the KE difference equal to the PE difference m*g*h and solve for height h.
 

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