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MAX/MIN problem

  1. Dec 5, 2006 #1
    Got It, Thanks Guys
     
    Last edited: Dec 5, 2006
  2. jcsd
  3. Dec 5, 2006 #2
    Right on, the min is 3.
    V=(Pi)R^2=54(Pi)
    A=2(Pi)RH+2(Pi)R^2
    Solve for H in volume, find minimum through first derivative.
     
    Last edited: Dec 5, 2006
  4. Dec 5, 2006 #3
    [tex] V = \pi r^{2}h [/tex]

    Thus

    [tex] A = 2\pi rh + 2\pi r^{2} [/tex]
     
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