MAX/MIN problem

  • Thread starter Jack Jiang
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  • #1
Got It, Thanks Guys
 
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  • #2
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An oil can is to be made in the form of a right circular cylinder to contain 54pi cubic inches. what dimensions of the can will require the least amt. of material.


did anyone get the radius to equal 3?

Right on, the min is 3.
V=(Pi)R^2=54(Pi)
A=2(Pi)RH+2(Pi)R^2
Solve for H in volume, find minimum through first derivative.
 
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  • #3
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[tex] V = \pi r^{2}h [/tex]

Thus

[tex] A = 2\pi rh + 2\pi r^{2} [/tex]
 

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