Maximize Revenue for Quadratic Problem at Movie Theatre

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The discussion centers around maximizing revenue for a movie theatre based on ticket pricing. The revenue equation provided, R = -40c^2 - 720c, is questioned for its validity, as it suggests negative revenue at low ticket prices, which is unrealistic. Participants agree that the equation likely contains a typo and should be R = -40c^2 + 720c instead. The correct approach involves finding the vertex of the parabola represented by the equation to determine the optimal ticket price. Clarification on the equation is essential for accurately solving the problem and maximizing revenue.
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A movie theatre sells tickets for $8.50 each. The manager is considering raising the prices but knows that for every 50 cents the price is raised, 20 fewer people go to the movies. The equation R = -40c^2 = 720c describes the relationship between the cost of tickets, c dollars, and the amount of revenue, R dollars, that the theatre makes. What price should the theatre charge to maximize revenue?

I believe what I need to do is find the maximum vertex of the parabola in order to solve the equation. So I did the following:

R = -40c^2 - 720c
= -40(c^2 - 18c)
= -40(c^2 - 18c + 9^2 - 9^2) <-- complete the square
= -40(c^2 - 18c + 81 - 81)
= -40[(c^2 - 9)^2 - 81)
= -40(c^2 - 9)^2 + 3240

Which would give me a vertex (9, 3240) but this does not make sense to me, I am not sure what I am looking for to be honest. I believe that the maximum price would be $9.00 to have a revenue of $3240, is this correct and I am just second guessing?
 
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You seem to be thinking in the right direction, although I did not analyze your work in detail. One spot of confusion is what you say, equation R = -40c^2 = 720c describes the relationship between the cost of tickets, c dollars, and the amount of revenue, R dollars, that the theatre makes", does not make sense. OOOOHHH, you mean -40c^2 - 720c = R, this could be better.
 
R = -40c^2 - 720c
= -40(c^2 - 18c)

You pulled out a negative but you left the 2nd term negative as well.

Double check the equation you were given, because you miswrote it in the problem, and it could have a mistake when you first started solving it.
 
Now I am fairly confused as it really does not make sense to me. I double checked the equation and I was correct in my work that it is the following:

R = -40c^2 - 720c

After correcting my mistake (that was pointed out by nickjer) I now have the following:

R = -40c^2 - 720c
= -40(c^2 + 18c)
= -40(c^2 + 18c + 81 - 81) <-- complete the square
= -40[(c^2 + 9)^2 - 81]
= -40(c^2 + 9)^2 + 3240

Which would give a vertex of (-9, 3240) which makes no sense to me in the context of the question. I am really not sure where to go from here.
 
Imperil said:
Now I am fairly confused as it really does not make sense to me. I double checked the equation and I was correct in my work that it is the following:

R = -40c^2 - 720c

Surely, this equation should be R=-40c^2+720c instead!:wink:
 
I have triple checked and it is definitely -720c which is why I am confused.
 
Imperil said:
I have triple checked and it is definitely -720c which is why I am confused.

It must be a typo!

If the equation were -40c^2-720c , then if you charged $1.00 per ticket, you would have a revenue of -$760.00; but revenue is always a positive quantity.

I would assume that the equation is supposed to be -40c^2+720c and just ask your instructor about it when you see him/her.
 
I thought this exact same thing but figured maybe I was thinking about it wrong! Thanks for your help, I just contacted my teacher by email regarding this. It is a key problem in my correspondence that I need to hand in, so I am shocked they included this typo.
 
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