Maximize Vol. of Cylinder w/ Conical End: Solution

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Homework Help Overview

The discussion revolves around maximizing the volume of a projectile shaped as a circular cylinder with a conical end, given a specific surface area. Participants are exploring the relationships between the dimensions of the cylinder and cone, including radius, length, and the angle of the cone.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss using Lagrange multipliers and partial derivatives to find optimal dimensions but express challenges in deriving the correct relationships. There are attempts to clarify the dependency of certain variables, such as the relationship between the angle and the dimensions of the cone.

Discussion Status

Some participants have provided insights into the relationships between the variables, while others are questioning the assumptions made in their equations. There is a recognition that the optimal values depend on a constant surface area, indicating a productive exploration of the problem.

Contextual Notes

There is mention of constraints from the original problem statement, including the requirement that the surface area equals a constant. Some participants are also clarifying misunderstandings regarding the nature of the answers provided in their reference materials.

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[SOLVED] Maximizing an Object

Homework Statement


What proportions will maximize the volume of a projectile in the form of a circular cylinder with one conical end and one flat end, if the surface area is given?

(there is a picture given with r being the radius, l being the length of the cylinder and s being the length of the cone(outside edge))

Homework Equations


The Attempt at a Solution



Well I can come up with:
SA = \pi*r^2+ 2\pi*rl + \pi*rs
V = \pi*r^2l + \pi / 3r^2*s*sin\theta

I've tried both using Lagrange multipliers and just using partial derivatives.
but haven't really come up with anything...
(r, l, s)
<2\pi rl + 2/3\pi*r*s*sin\theta, \pi r^2 + 0, 1/3\pi*r^2*sin\theta> = \lambda*(<2\pi r + 2\pi l + \pi s, 2\pi r, \pi r>
Then with using the 3 equations I was getting r = 2l and l = lamda, which isn't the case, so I think I must either need another equation or my equations are wrong?
 
Last edited:
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What is wrong here is that sin(theta) is NOT independent of s and r!
Hence, you cannot treat it as a constant.


Use therefore the relationship: s\sin\theta=\sqrt{s^{2}-r^{2}} in your volume formula.
 
Thanks for your reply, I am able to get a few relationships between s, r, l, but I can't seem to get the answer yet. (ie r = sqrt(5), s = 3)
I can get
\sqrt{s^2-r^2} = \frac{2}{3} s
r = \sqrt{5} / 3 s
\lambda = r/2
Will my lambda need to change throughout the problem? I seem to consistently be getting the same one, but for whatever reason I can't seem to solve the damn thing.
 
Last edited:
jesuslovesu said:
Thanks for your reply, I am able to get a few relationships between s, r, l, but I can't seem to get the answer yet. (ie r = sqrt(5), s = 3)
I can get
\sqrt{s^2-r^2} = \frac{2}{3} s
r = \sqrt{5} / 3 s
\lambda = 2/r
Will my lambda need to change throughout the problem? I seem to consistently be getting the same one, but for whatever reason I can't seem to solve the damn thing.

I don't get what you are saying.

You have FOUR equations given:
The three "gradient" equations, along with the requirement that the surface area equals some constant C.

Your optimal values of r, s and l (and lambda) will depend upon that C as a parameter.
 
My apologies, the book I'm using put the answer in terms of a ratio, I was thinking it was an actual numerical answer.
 
jesuslovesu said:
My apologies, the book I'm using put the answer in terms of a ratio, I was thinking it was an actual numerical answer.

Well, a known ratio is an actual numerical answer, it just shows that there are several combinations that maximizes the volume of the object
in question.
It is directly related to the parameter-based approach I'd prefer.
 

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