Maximizing Function Increase: Understanding Directional Derivatives

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Homework Help Overview

The discussion revolves around understanding the concept of directional derivatives in the context of a function of two variables. The original poster is exploring the direction in which the function does not increase, particularly in relation to the gradient vector.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the gradient and the directional derivative, questioning how to identify directions of non-increase. There is mention of the condition for the directional derivative being less than zero and the implications of being perpendicular to the gradient.

Discussion Status

The conversation is ongoing, with participants providing hints and clarifications regarding the relationship between the gradient and the directional derivative. Some participants are exploring the implications of being perpendicular to the gradient, while others are questioning the original poster's assumptions and seeking further clarification.

Contextual Notes

There is a focus on the mathematical properties of directional derivatives and gradients, with an emphasis on understanding the geometric interpretation of these concepts. The original poster is seeking guidance on how to find specific vectors related to these properties.

Master J
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I have a function of 2 variables. I know it increase most rapidly in the direction of the gradient, but how about in wht direction is it not increasing?

I am thinking that the gradient (dot product)(direction in which it is not increasing) = 0

Any hints?
 
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Well, since you mentioned the word "directional derivative" anyway: you could check for which [itex]\vec v[/itex]
[tex](\vec\nabla f(x, y)) \cdot \vec v < 0[/tex]
?
 
Yes, it is true that [itex]\vector{\nabla f}\cdot \vector v[/itex] is the directional derivative in the directional derivative in the direction of [itex]\vec{v}[/itex] (for [itex]\vec{v}[/itex] of length 1). And that tells you the derivative is 0 perpendicular to the gradient.

(CompuChip, surely you didn't mean "<"?)
 
Err, no comment? :)
 
That is what is was thinking, since of course cos(pi/2) = 0. So the vector that is at a right angle to the gradient is in the direction of zero increase. But how do I go about finding this vector?
 

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