Maximizing the Isoperimetric Problem with Integral Constraints | MathWorld

  • Thread starter Thread starter HACR
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the isoperimetric problem, which seeks to determine the shape that maximizes area for a given perimeter. Integral constraints related to arc length are examined, specifically in the context of the Calculus of Variations. Participants highlight the connection between maximizing integrals and finding extrema of functions with two variables. The Euler-Lagrange equation is referenced, with a specific focus on the expression -u"/(1+(u')^2)^(3/2) and its derivation.

PREREQUISITES
  • Understanding of the isoperimetric problem in calculus
  • Familiarity with the Calculus of Variations
  • Knowledge of the Euler-Lagrange equation
  • Basic concepts of integral calculus
NEXT STEPS
  • Study the derivation and applications of the Euler-Lagrange equation
  • Explore advanced topics in the Calculus of Variations
  • Investigate the relationship between the isoperimetric problem and the brachistochrone problem
  • Review examples of maximizing integrals under constraints
USEFUL FOR

Mathematicians, physics students, and anyone interested in optimization problems in calculus, particularly those focusing on geometric constraints and variational principles.

HACR
Messages
35
Reaction score
0

Homework Statement


The isoperimetric problem is of the finding the object that has the largest area with the equal amount of perimeters; however, how does the integral constrained by the arc length get maximized? http://mathworld.wolfram.com/IsoperimetricProblem.html


Homework Equations





The Attempt at a Solution


...finding a point at which the integral is like finding the max and min of a function of two variables...
 
Physics news on Phys.org
HACR said:

Homework Statement


The isoperimetric problem is of the finding the object that has the largest area with the equal amount of perimeters; however, how does the integral constrained by the arc length get maximized? http://mathworld.wolfram.com/IsoperimetricProblem.html

The Attempt at a Solution


...finding a point at which the integral is like finding the max and min of a function of two variables...

The general subject is Calculus of Variations. One place to read about it is here:

http://www.google.com/url?sa=t&rct=...sg=AFQjCNGZoq3YfZweM8ZFKBWuB062RSvkZQ&cad=rja
 
It says the shortest path is the straight line; however, the brachistochrone problem proves that it is actually a curved line on which a stone could accelerate more. OK, brachistochrone problem is discussed. But why is on page 1163, the Euler Lagrangian equal to [tex]-\frac{u"}{(1+(u')^2)^{\frac{3}{2}}}[/tex]? I got -u"+(u')^{2}u" for numerator.
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K