- #1

PhysicsStudy

- 6

- 0

## Homework Statement

Calculate the maximum flow rates through the Francis and the Samson turbines under the conditions specified:

Table 1 Characteristics of some American water turbines, 1849–97, on the basis of 30-inch (760 mm) wheel and 12-inch (300 mm) head

Type | Maximum power output | Efficiency (%)

Francis | 0.15 kW / 0.20 horsepower| 79.7 at full power / 55.0 at half power

‘Samson’ | 1.38 kW / 1.85 horsepower | 82.0 at full power / 75.6 at half power

## Homework Equations

Power = turbine efficiency * density of water * acceleration due to gravity * head * flow rate

so

Flow rate = Power / (turbine efficiency * density of water * acceleration due to gravity * head)

## The Attempt at a Solution

Does anyone know if the efficiency in this equation should be given as a percentage or fraction? i.e. 79.7% or 0.797

Francis example...

Density of water = 1000kg/m^3

Acc due to gravity = 9.81 m/s^2

At full power:

Flow rate = 150/(0.797*1000*9.81*0.3)=0.064m^3/s

At half power:

Flow rate= (150/2)/(0.55*1000*9.81*0.3)=0.046m^3/s

However I have a feeling I'm missing a step. I'd be grateful for anyone who could take a look. :) Thanks.

Last edited: