Maxwellian velocity distribution

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As the absolute temperature of an ideal gas approaches 0 K, the classical Maxwellian velocity distribution becomes ineffective, transitioning instead to quantum statistical distributions like Fermi-Dirac or Bose-Einstein. This shift occurs because the quantum nature of particles becomes significant at ultra-low temperatures, rendering classical models inadequate. At these temperatures, the gas condenses and no longer behaves as a gas, which is why the Maxwellian distribution is not applicable. Understanding these concepts requires knowledge of quantum mechanics, as classical thermodynamics fails to account for quantum effects. The discussion emphasizes the importance of transitioning to quantum statistics for accurate descriptions of particle behavior at low temperatures.
samreen
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hey, I've just begun on elementary concepts in heat and thermodynamics. nd i was wondering...for the probabilistic maxwellian distribution of velocities in an ideal gas, as absolute temperature of the gas system tends to 0 K, the distribution plot will tend to the delta function, wnt it? can anyone please explain if this is what will happen, and if yes, what's the actual physical significance of this result? [please assume i dnt kno anything, and explain everything :) ]
 
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samreen said:
hey, I've just begun on elementary concepts in heat and thermodynamics. nd i was wondering...for the probabilistic maxwellian distribution of velocities in an ideal gas, as absolute temperature of the gas system tends to 0 K, the distribution plot will tend to the delta function, wnt it? can anyone please explain if this is what will happen, and if yes, what's the actual physical significance of this result? [please assume i dnt kno anything, and explain everything :) ]

As the temp approaches 0K,maxwellian distribution is no longer effective
You should use quantum statistics like Fermi-Dirac distribution or Bose-Einstein distribution at ultra-low temp
 
thanx...im cluless bt the other 2 tho
 
why does maxwells breakdown or whatever, for low T?
 
samreen said:
why does maxwells breakdown or whatever, for low T?

As temp goes ultra-low,the quantum nature of the particles (atoms,molecules.ions,etc) becomes more significant,so the classical Maxwell-Boltzman distribution,which neglects all quantum effects, no longer applies.
 
the gas will condense, itl no longer be a gas. so maxwells distribution ought not to apply. I've got it partly.
 
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