Me solving 2 electrical network problems

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The discussion revolves around solving two electrical network problems using Thevenin's theorem. In the first problem, the user calculates the current through a 5Ω resistor, arriving at a voltage of 14.28V and a Thevenin resistance of 1.1428Ω, leading to a current of 2.34A, which contradicts the expected answer of 4A. The second problem involves finding the current through a 24Ω resistor, where the user derives a Thevenin voltage of 15V and a short-circuit current of 0.48A, resulting in a current of 0.271A through the resistor. Users are encouraged to provide feedback and assistance, but there is an issue with an image link that cannot be accessed. Clarification and further assistance are requested to resolve the discrepancies in the calculations.
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please help me solving 2 electrical network problems

file:///C:/Documents%20and%20Settings/user/My%20Documents/My%20Pictures/From%20RSPC_Pashya/Camera%20roll/WP_000127.jpg

In first problem I have to find current through 5Ω resistor using Thevinins eq.

So, in first step i removed 5Ω resistor with open ckt. hence Ix=0 hence the dependent source becomes zero. 4A+1A that is 5A going up. then kcl at above node yields me node voltage 14.28v

so my vth comes 14.28v

now, as Ix becoming zero and dependent source becoming zero we can calculate Rth=1.1428Ω
so to find current thru 5Ω

I will be 14.28/6.1428... hence i got answer as 2.34A.

But answer given to me is 4A.

please help.

In second problem also we need to find current through 24Ω using Thevinins eq.

I applied kvl at input side & kcl at output side got two equations
8Ix-Vx=16
130Ix+Vx=0

solving i got Vx=15v == Vth

then solved for Isc which i got 0.48A
Current throgh 24 ohm i got 0.271A

am i correct?

please help
 
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welcome to pf!

hi pforpashya! welcome to pf! :smile:
pforpashya said:
file:///C:/Documents%20and%20Settings/user/My%20Documents/My%20Pictures/From%20RSPC_Pashya/Camera%20roll/WP_000127.jpg

erm :redface:

i can't see the picture …

it's still on your computer! :wink:
 

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