Mean field theory in the Heisenberg model

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SUMMARY

The discussion focuses on the application of mean field theory in the Heisenberg model, specifically addressing why the average of spin flip terms, and , equals zero. This is established by convention, where the mean field is oriented such that the system magnetizes in the z direction, leading to zero magnetization in other directions. The uniform magnetization is represented as = = M , with being a unit vector aligned with the z direction.

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  • Understanding of mean field theory
  • Familiarity with the Heisenberg model
  • Knowledge of magnetization concepts in statistical mechanics
  • Basic proficiency in vector notation and coordinate systems
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  • Study the derivation of mean field approximation in the Heisenberg model
  • Explore the implications of uniform magnetization in different coordinate systems
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This discussion is beneficial for physicists, particularly those specializing in condensed matter physics, as well as students and researchers interested in magnetic systems and statistical mechanics.

Jeff Chen
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I have a problem about Heisenberg model.When applying mean field approximation,why does the average of spin flip terms be zero(<S+>=<S-> = 0 )? Thanks
 
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It's just a convention - you take the "mean field" such that the system magnetizes in the z direction, and take the magnetization in the other directions to zero.

More generally, in an arbitrary coordinate system, you assume that the system has a uniform magnetization given by
$$
\mathbf{M} = \langle \mathbf{S}_i \rangle = M \hat{e}
$$
where ##\hat{e}## is a unit vector in some direction. Now just choose your coordinate system such that the z direction points along ##\hat{e}##, and then you have ##\langle S^+ \rangle = \langle S^- \rangle = 0## in that coordinate system.
 

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