grounded
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reilly said:Your case would be greatly strengthed if you could give the mathematical formulation of your distance ideas.
Did you happen to read post #52?
reilly said:Your case would be greatly strengthed if you could give the mathematical formulation of your distance ideas.
Einstein didn't "claim" it, he used the already known fact as the first postulate in his new theory. Big, big difference.grounded said:Wasn't it Einstein who claimed it [C] must be the same for all frames of reference?
Take what out of what formula?I still don’t think you understand my point. In order for you to measure a relative effect, you have to take something out of a formula that we know works.
grounded said:Did you happen to read post #52?
grounded said:This is what happens when you DO NOT include your distance traveled:
(Only the distance the passing car travels in one second) (80.66 Feet)(This is a known value)
grounded said:Tom, where did Maxwell discuss relative measurements of light? I was under the impression that Maxwell only discussed light from an, at rest relative to the source point of view.
Wasn't it Einstein who claimed it must be the same for all frames of reference?
Didn't Maxwell basically say that since space offers no resistance to light, than no matter how fast the source is traveling, the light would always travel away from the source at the speed of light? Which one of MAXWELL'S equations (please try to keep it in layman terms) describes what we will measure if the light source is traveling towards us?
I still don’t think you understand my point.
In order for you to measure a relative effect, you have to take something out of a formula that we know works.
Tom Mattson said:Grounded, we all understand it. That's because we all studied non[/color]relativistic physics before learning SR. It's just that you aren't understanding what we are saying. Let me explain.
What Russ and I have been telling you, and what you aren't understanding, is this:
The wavelength of the light in the rest frame of the source is not special. There's no reason to think that it is the "correct" wavelength, while all others are only "apparent". There's no reason whatsoever to use any correction for the distance the observer has traveled, and I'll explain why later on.
tom_mattson said:But the deduction is not true: The speed of light is the same in every frame.
I don't think you are seeing exactly how SR connects to your argument.
But the theory was not developed to account for wavelength measurements. The theory was developed for the exact reason I said it was developed: To maintain the invariance of the equations of electrodynamics when transforming from one inertial frame to another.
tom_wattson said:You said you came here to talk to professionals about this, yes? Please take the advice of this professional: You are never going to get out of these circles you are stuck running around in until you understand the problem above.
No problem on my end. The question is, will you do the same?
Understanding it is no problem. Your points are nothing new to me: physicists have to study nonrelativistic physics before learning SR. It's not that I don't understand you, it's that I understand that you are wrong.
tom_mattson said:And now we come to Prejudice #1, that you must abandon if this is to make any progress. When you say that the speed of light is not the same to all observers, the logical implication is that Galilean relativity is correct and Special relativity is wrong. That is why I attempted to explain to you why this cannot be so. You can't state what you state on the one hand, and then refuse to listen to why it's wrong on the other, and expect this discussion to get anywhere.
I wish you were more interested in learning physics, because you would know that you would not be ridiculed for saying this. Do you know why?
tom_matteso said:Because I used the exact same approach in my post on Maxwell's equations.[/color]
I started with classical EM theory, and I assumed that SR was wrong, and I derived a prediction that is contrary to what we observe.
OK
OK again.
Not OK.
You are wrong when you say that this is the "only way", and I know that I have explained it more than once in this thread. Please do what you ask of the rest of us and listen[/color] to our responses.
Again, with emphasis: There is no reason whatsoever to state that the observer has traveled any distance. Your statement reflects Prejudice #2, which you also must abandon: There is no way to even define[/color] absolute motion. We are not forced to say that the obserer is moving 10 MPH. We are perfectly free to say that the observer is at rest, and that the car under observation is moving towards him at 65 MPH (notice that I'm not taking SR into account). All the observer has to do is take the 65 MPH, multiply by the time required to pass, and we get the correct length.
Same basic flaws.mat_mattson said:That is exactly what we do when we make measurements.[/color]
Yes. But unlike you, I also notice the differences[/color]. This brings us to Prejudice #3, which you also must abandon if you are to see your way out of this error. Specifically, you are prejudiced towards the opinion that a stream of light pulses can be treated in the same way as a stream of cars. It can't![/color].
You are correct in saying that an observer errs in making a measurement of the length of the car using its ground speed of 55 MPH when the observer's own ground speed is 10 MPH in the other direction. The reason you are correct is that there is (according to pre-relativity) a relative velocity[/color] of 65 MPH between the two cars, and that is what must be used to get a correct result.
But what happens when we look at light? The relative speed never changes[/color], no matter what the speed of the source. The relative velocity between a light pulse and any observer is c. And since the speed of light is the same for everyone, no frame has any special claim to knowledge of the "correct" wavelength of any light pulse. All measurements are equally valid for their respective frames.
Your entire case rests on a rejection of that fact, and that is why you are wrong.
edit: typo
wespe said:The answer comes out wrong because of dividing the speed wrt the road by the frequency wrt the observer. You can't mix measurements made wrt different frames.
Tom Mattson said:But we can see that he isn't transcending anything. He is making choices that lead to the physics of the 19th century, and we know that those choices are wrong.
grounded said:The relative frequency of the light measured by the observer while in motion = 190,000 cycle per second
The relative distance traveled in one second, divided by the relative frequency, equals the relative wavelength, right?
So (186,000 + 4,000) divided by 190,000 equals the wavelength (1 mile) Agree?
grounded said:The part of the formula that you throw out is “the distance the observer has traveled relative to the source”.
...
THIS NUMBER IS CAUSED BY INCORRECT MATH; IT IS NOT CAUSED BY SR.
swansont said:No. Tell me how this doesn't imply that I am measuring the light to be moving at 190,000 miles/s
swansont said:If you shine laser light of the right wavelength on an atom, it will absorb that light. If the atom starts moving, that absorption slows and stops as the light moves out of resonance - the color has changed. How is the atom "ignoring" the amount that it has moved? It isn't doing any math, AFAIK.
grounded said:EXACTLY
grounded said:The distance light travels away from the source in one second = 186,000 miles
The distance the observer travels towards the source in one second = 4,000 miles
The wavelength of the light while at rest relative to the source = 1 mile
The above are known because we set up the experiment.
The relative frequency of the light measured by the observer while in motion = 190,000 cycle per second
The relative distance traveled in one second, divided by the relative frequency, equals the relative wavelength, right?
So (186,000 + 4,000) divided by 190,000 equals the wavelength (1 mile) Agree?
The part of the formula that you throw out is “the distance the observer has traveled relative to the source”.
You throw it out by not including it into the scale of the equipment used to measure the speed or wavelength, which is why you will always measure the total relative distance traveled by the light and the observer to be 186,000 miles.
I agree that you are not consciously throwing this out; you just never realized it was missing.
If you do not include the 4,000 miles the observer has traveled you will measure the following:
THIS NUMBER IS CAUSED BY INCORRECT MATH; IT IS NOT CAUSED BY SR.
(186,000 + 0) divided by 190,000 = .9789 miles
Is not that the wavelength you predict the observer will measure due to SR?
If you tell me that you are dividing the frequency into 186,000 miles because that is what you measured, then I’m telling you that you are measuring it wrong.
Since we set up the experiment, we know the observer is traveling towards the source at 4,000 miles per second. We also know that light will travel away from the source at 186,000 miles per second. We do not really even have to measure these values. We know the total relative distance traveled is 190,000 miles per second.[/color]
The observer knows he is traveling towards the light source at 4,000 miles per second.
The observer knows the light will travel 186,000 miles away from the source in one second.
The observer knows the relative distance traveled is 190,000 miles per second, this is a fact.
wespe said:By MEASURING the relative speed of light wrt ourself, we already account for the traveled distance.
grounded said:Where? Can you tell me where the oscilloscope, or the interferometer, or what ever you used to measure the speed accounted for the distance traveled relative to the source?
geistkiesel said:Some observations on the corfrectness of information exchange re om_Mattson v Grounded.
You can use your theory all day long, but when you get to the "we can look from the train frame of the stationary frame equivalently, that I drop out of the conversation
grounded said:Where? Can you tell me where the oscilloscope, or the interferometer, or what ever you used to measure the speed accounted for the distance traveled relative to the source?
grounded said:Where? Can you tell me where the oscilloscope, or the interferometer, or what ever you used to measure the speed accounted for the distance traveled relative to the source?
wespe said:What do you think relative speed is?
Consider please:
You are in a spaceship x meters long. There are windows on the front and back. Someone far away sends a light signal. You let the signal pass through your windows. You take note of the times when light enters the front window and exits from the back window. So you can calculate deltaTime. Now you can calculate speed of light as x/deltaTime. You find it to be 300.000 km/sec. That is the relative speed of light wrt you. Because all of them were your measurements. You don't care about the distances anyone traveled wrt something else, you just measure how long it took for light to pass the distance on your ship. So you measured the relative speed of light wrt you.
wespe said:the distances traveled are accounted by the moving objects themselves, when relative speed is measured. Because, relative speed is the approach speed, if you will understand that term better. Approach speed is directly measured by the observer. If you try to calculate it by adding or subtracting speeds of the objects wrt something else, then the answer you get will not match the directly measured speed.
grounded said:Currently we calculate the relative speed of light from measurements of the frequency or the wavelength, but we always divide them into 186,000 miles.
grounded said:This is a theoretical experiments created off SR, but if it was done it would agree with what I am saying.
Currently we calculate the relative speed of light from measurements of the frequency or the wavelength, but we always divide them into 186,000 miles.
Relative speed is the sum of the distance traveled by both objects in one second.
The relative speed between car “A” and car “B” is equal to the sum of the distance car “A” has traveled in one second, added to the distance car “B” has traveled in one second.
60 miles in one second, added to 40 miles in one second, equals a relative speed of 100 miles per second.
How do you define relative speed?
People say we can’t measure the speed of light like this because of SR. Fine.
If that is so, we should be able to measure the speed of light, as done above, and clearly see the effect of SR. But we won’t.
We currently do not include the distance traveled by the observer (speed) when we calculate the relative speed (total relative distance traveled per second), which guarantees a constant speed of light, no matter what.
Don’t you think it’s odd that we have to change the formula in order to measure SR effect?
By change I mean, replace “relative speed” with “speed of light” as shown below.
SPEED OF LIGHT divided by RELATIVE FREQUENCY equals RELATIVE WAVELENGTH
Instead of:
RELATIVE SPEED OF LIGHT divided by RELATIVE FREQUENCY equals RELATIVE WAVELENGTH
If SR is valid, why can't we measure its effect using normal means.
grounded said:Can you put this in a car "A" and car "B" perspective with math and show how the distance car "B" travels is accounted for?
grounded said:Can you put this in a car "A" and car "B" perspective with math and show how the distance car "B" travels is accounted for?
Yes. I was thinking of first defining the scene from a third perspective, then transforming for A and B as Galilean. And show that the traveled distance is accounted for, despite approximately correctly for low speeds.Tom Mattson said:Whether you are using Galilean relativity or SR, the equation is the same.
We currently do not include the distance traveled by the observer (speed) when we calculate the relative speed (total relative distance traveled per second), which guarantees a constant speed of light, no matter what.
That is my whole point...Tom Mattson said:Right. We calculate it that way because it agrees with measurements.
Tom Mattson said:Whether you are using Galilean relativity or SR, the equation is the same.
Tom Mattson said:v=(x2-x1)/(t2-t1)
grounded said:That is my whole point...
The above formula has nothing to do with calculating relative speed.
Integrate the formula.
All this formula does is calulate the amount of time it takes light to travel from the source to the point it was detected.
Your speed has nothing to do with anything in this formula except that it will alter the distance light can travel before you detect it.
Tom Mattson said:Right. And the ratio of those two quantities is the speed of the light relative to me.
That formula is the very definition of relative speed.