Measuring torque acting on motor shaft?

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Discussion Overview

The discussion revolves around measuring the average torque exerted by an electric motor on an auger used for dispensing pet food. Participants explore methods to determine motor efficiency and torque, considering the motor's characteristics and operational parameters.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant seeks to measure average torque and questions how to find the motor's efficiency at different voltage inputs, noting limited information about the motor's type.
  • Another participant identifies the motor as likely being DC and suggests looking for similar motors to estimate efficiency, providing a link to a resource.
  • A different participant proposes measuring torque directly by assessing the torque applied to the motor's mount or using a sensor between the motor and auger.
  • One participant advises against focusing on efficiency initially, stating that it varies with the motor's operating point and suggesting that the torque constant can be deduced from speed versus voltage curves.
  • A technical correction is made regarding the power output formula, emphasizing that torque is a physical quantity while RPM is a unit of measure.

Areas of Agreement / Disagreement

Participants express differing views on the importance of measuring efficiency at this stage and the methods for determining torque, indicating that multiple competing approaches and uncertainties remain in the discussion.

Contextual Notes

Participants acknowledge limitations in their understanding of the motor's characteristics and the complexity of measuring torque directly, which may require sensitive instrumentation.

robertjordan
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I have an electric motor that I am using to turn an auger to dispense pet food. I want to measure the average torque required to turn this auger at a given rpm.

I know Powerin = Voltage into motor * Current into motor
and Powerout = Torque exerted by shaft * RPM of auger
and Powerout = Efficiency of motor * Powerin

But how can I find the efficiency of the motor at different voltage inputs? I don't know anything about this motor (I don't even know if it's an AC or DC motor) beyond that it works when connected to a battery and that it changes directions when I swap the leads. How can I find average torque exerted on the shaft by the pet food? I can measure RPM, VoltageIn, and CurrentIn...
 
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I wouldn't worry about efficiency yet because it varies depending on the motor's operating point. The torque constant can be deduced from speed versus voltage curves. Speed and voltage are easy to measure. From what I've seen, measuring torque directly of a small DC motor requires comparatively elaborate and sensitive instrumentation.

Anyway, let's assume, for example, you want your motor to operate at maximum efficiency. In that case you then want the torque absorbed by the auger to equal the torque produced by the motor at the motor's maximum efficiency speed.

Technical correction: In the power out formula, torque is a physical quantity, whereas RPM is a unit of measure. I think you'd like all the variables to be physical quantities in this type of equation.
 

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