Mech - Girder Section - Picture included

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Homework Help Overview

The discussion revolves around a mechanics problem involving a girder section and the balance of weights on support points. Participants are exploring how to analyze the forces and moments acting on the structure based on a provided image.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning whether the weights on the supports are equal or if they need to be calculated using dimensions represented by letters. There is a discussion about taking moments and using relative distances, despite the absence of specific measurements.

Discussion Status

The conversation is ongoing, with some participants suggesting methods to approach the problem, such as using unit distances to simplify calculations. There is no explicit consensus on the method to be used, and multiple interpretations of the problem are being explored.

Contextual Notes

Participants note the lack of specific distance measurements and express a need for resources to better understand support structures in mechanics.

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Homework Statement



http://img132.imageshack.us/img132/8958/mechanicsgv3.jpg

The Attempt at a Solution



(i) Is the weight balanced on both sides in a situation like this, in which case it would be:

(6000 +3000) / 2 = 4500N on A and 4500N on G

Or are the weights not equal and infact I am meant to work it out with dimensions in terms of letters, for example A-C?

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(ii) Could anyone tell me where i can learn about these support structures, i brought a mechanics book but it doesn't cover and after looking on the internet i can't find any good sources of information to teach me.
 
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Spadez said:
Or are the weights not equal and infact I am meant to work it out with dimensions in terms of letters, for example A-C?

Hi Spadez! :smile:

No, they're not equal.

Hint: take a moment.
 
Ok, so i take moments but i have to use the distance with respect to the letters, I am not given any distances. Can i still do it like that?
 
hmm … assuming the triangles are all the same, just say "let AC = CE = EG = 1 unit" … the units will cancel in the end :smile:
 

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