Mechanics of material: an Axial Load Problem

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SUMMARY

This discussion focuses on the mechanics of axial load problems involving a beam EF, a rod CD, and a rod AB, with specific attention to equilibrium and compatibility equations. The equilibrium equation derived is ME = 0, leading to the relationship FAB = 2(FCD + Fsp). Compatibility equations are established using thermal expansion and force relationships, specifically δABt = αal. ΔT.LAB and δCDF = (FCD + Fsp) / (kCD + ksp). The gap between CD and EF is noted as 0.1 mm, which is crucial for understanding the system's constraints.

PREREQUISITES
  • Understanding of axial load mechanics
  • Familiarity with thermal expansion concepts
  • Knowledge of equilibrium and compatibility equations
  • Basic principles of spring mechanics
NEXT STEPS
  • Study the derivation of equilibrium equations in structural mechanics
  • Learn about thermal expansion coefficients and their applications
  • Explore compatibility equations in multi-body systems
  • Investigate spring constant calculations for different materials
USEFUL FOR

Mechanical engineers, structural analysts, and students studying mechanics of materials will benefit from this discussion, particularly those dealing with axial load problems and thermal effects on structural components.

dikimbi2
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Hey Guys, here is a skeleton for an exercise I need a help with:

mr8oyf.jpg


In this Problem we have a beam EF which is pin-supported at E, a Rod CD which is enrolled by a spring ( spring constant =k) and a rod AB (AB is touching the ground, I forgot to draw it).

If we heat the Rod AB what will be the equation of equilibrium and the compatibility equations to find the forces FAB, FCD and Fsp (the force of the spring).

(Gap between CD and EF is equal to 0.1 mm)

I just want to know the equations because I don't remember the rest of the numerical given.

Thanks everyone,
Dikimbi2.
 
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Again Hi, sorry I forgot to show you what I did: (I had this in an exam):

Equilibrium equation: (Moment about point E) ME = 0 =>

FAB = 2(FCD+Fsp)

Compatibility equations: [(δAB)t – (δAB)F]/1 = [(δCD)F]/2 (Using Thales)

AB)t = αal. ΔT.LAB

AB)F = (FAB.LAB)/(AAB.EAB)

CD)F = (FCD + Fsp) / (kCD + ksp)

with kCD = (ACD.ECD)/(LCD)

The Other Compatibility equation is: (δ'CD)=(δsp)

δ'CD = (FCD)/(kCD)
sp = (Fsp)/(ksp)
 

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