Mesh analysis and power dissipation

AI Thread Summary
In mesh analysis, the power dissipation in resistors must equal the power supplied by voltage sources. To solve for power dissipation, first determine the current in each branch and calculate the power for each resistor using the formula PR = I²R. Sum these power values to find the total power dissipated in the network. Additionally, calculate the power contribution from voltage sources with PS = Vs⋅I, ensuring to consider the orientation of the voltage source and the direction of current. Finally, confirm that the total power dissipated equals the total power supplied, demonstrating that ∑PR = ∑PS holds true.
Andriy B
Messages
2
Reaction score
0
Hi I'm taking an intro course to electrical and computer engineering and I'm having trouble figuring out part c of number one. I have attached a copy of my solutions to parts a and b which I believe are right (correct me if I'm wrong please) however when I calculate the power dissipation of each component and add them up I get a large number. Thank you in advance.
 

Attachments

  • Matlab_HW_2.pdf
    Matlab_HW_2.pdf
    199.6 KB · Views: 437
  • IMG_0300 (1).JPG
    IMG_0300 (1).JPG
    48.8 KB · Views: 760
Engineering news on Phys.org
" Determine the power dissipation of each component and show that the sum of the power dissipated equals zero "

Somebody was drunk while writting that assignement ? Dissipative components in that mesh are resistors. Sum of powers dissipated in them must be equal to sum of powers delivered by voltage sources.
 
So what's the correct way to solve part c?
 
After you find current of each branch, calculate power dissipated by every resistor (PR=IR2R).Sum these powers up to find total power dissipated in network. Power contribution of voltage source calculate as PS=Vs⋅I, where I is current through the source (pay attention to voltage source orientation and current flowing through it, depending on network parameters it may be negative). Then show that ∑PR= ∑PS holds
 
Thread 'Weird near-field phenomenon I get in my EM simulation'

Thread 'Weird near-field phenomenon I get in my EM simulation'

I recently made a basic simulation of wire antennas and I am not sure if the near field in my simulation is modeled correctly. One of the things that worry me is the fact that sometimes I see in my simulation "movements" in the near field that seems to be faster than the speed of wave propagation I defined (the speed of light in the simulation). Specifically I see "nodes" of low amplitude in the E field that are quickly "emitted" from the antenna and then slow down as they approach the far...
View full post »

Thread 'EMF (Electromagnetic Field) & EHS (Electromagnetic Hyper Sensitivity)'

Hello dear reader, a brief introduction: Some 4 years ago someone started developing health related issues, apparently due to exposure to RF & ELF related frequencies and/or fields (Magnetic). This is currently becoming known as EHS. (Electromagnetic hypersensitivity is a claimed sensitivity to electromagnetic fields, to which adverse symptoms are attributed.) She experiences a deep burning sensation throughout her entire body, leaving her in pain and exhausted after a pulse has occurred...
View full post »

Similar threads

What are these possible heat dissipation tubes?
Replies
11
Views
1K
Calculating the Power Dissipation of a Wire
Replies
23
Views
7K
Why do powerplants sell electricity for a negative price?
Replies
10
Views
1K
AC Circuit Analysis: Solving Example with Confusing Concepts
Replies
3
Views
2K
Calculating Resistivity across a mesh sheet
Replies
7
Views
5K
Power dissipated in this circuit with 2 batteries and 3 resistors
Replies
22
Views
4K
How are coils arranged in a power station generator?
Replies
8
Views
4K
Is Mesh Analysis Really Necessary in Electrical Engineering?
Replies
4
Views
2K
Maximum Power dissipated at load resistor
Replies
3
Views
884
Electrical Machines and Power Flow
Replies
6
Views
2K

Hot Threads

Recent Insights

Back
Top