Method of Sections: Solving Truss Moment & Force Equations

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SUMMARY

The discussion focuses on the application of the method of sections for solving truss moment and force equations. The user struggles with calculating moments and forces accurately, particularly in determining when to use sine and cosine functions. Key equations presented include the moment equation at point C and the force equations in both x and y directions. The importance of sketching the section and isolating the relevant part of the truss for equilibrium analysis is emphasized as a critical step in the problem-solving process.

PREREQUISITES
  • Understanding of truss structures and their components
  • Proficiency in static equilibrium principles
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Ability to perform moment calculations in mechanical systems
NEXT STEPS
  • Study the method of sections in truss analysis
  • Learn how to effectively sketch free-body diagrams for trusses
  • Review trigonometric identities and their applications in engineering problems
  • Explore advanced equilibrium analysis techniques for complex structures
USEFUL FOR

Structural engineers, civil engineering students, and anyone involved in analyzing truss systems and static equilibrium problems will benefit from this discussion.

D0m
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Hi guys I am having trouble taking the moment after i cut the truss, the answear always seems to be off. I attached my work in the attachements. Can you check if my equations are right.

for moment: Mom@c=0: (ACx2.2)+(18.72x2.2)+(24x2.2)=0, AC=42.7??
sum of all forces in x direction: Fx=0: -24+AC+BD+BCsin(30)=0
sum of all forces in y direction: Fy=0: -18.72+BCcos(30)=0

****One of my main problems is the cos and sine values because some times x is cos and sometimes its sine when you doing trusses is there a trick on how i can tell which one to use?****
 

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In the method of sections you should draw a diagram to show where you have taken a section. In your first eqn, you start with the statement Mom@c=0 but go on to say AC x 2.2 etc But Force AC passes through c. So, taking moments about C should result in a zero moment contribution from the force AC.. The rest of your equation contains forces to the left and tot the right of C. This underlines the importance of sketching where the section is that you are considering and isolating that part of the frame (to the left or to the right of your section) about whose equilibrium you intend to make a statement. We could deal with sin and cos after you have started correctly.
 

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