Metric for Lambdavacuum EFE - Radial Coordinates

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I am having trouble finding the equation for the metric for the Lambdavacuum solution to the EFE in radial coordinates. Any suggestions?
 
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The metric doesn't change with the addition of the Lambda term. So, it's the same as the metric of a 2-sphere. Can you get that?

EDIT: I didn't see you were looking for a vacuum solution. The metric should then be the Minkowski Metric.
 
Last edited:
The vacuum field solution of empty space with no cosmological constant produces the Minkowski metric:

\begin{equation}

d\vec{s}^2=d\vec{x}^2-dt^2

\end{equation}In radial coordinates, the vacuum field solution around a spherical mass produces the Schwarzschild metric:

\begin{equation}

\begin{split}

d\vec{s}^2&=\left(\frac{1}{1-\frac{\vec{r}_s}{\vec{r}}} \right) d\vec{r}^2 + \vec{r}^2 \left(d\theta^2 + \sin^2\theta d\varphi^2 \right) -\left(1 - \frac{\vec{r}_s}{\vec{r}} \right) dt^2

\end{split}

\end{equation}Which as ##\vec{r}\to \infty## becomes the Minkowski metric, where ##\vec{x}=[\vec{r}, \theta, \varphi]##.I am still not sure how to write metric of the Lambdavacuum solution. What is ##d\vec{s}^2## as a function of ##\Lambda## and ##g_{\mu \nu}##?.
 
redtree said:
I am still not sure how to write metric of the Lambdavacuum solution

It's the de Sitter metric; see here:

https://en.wikipedia.org/wiki/De_Sitter_space

If by "radial coordinates" you mean coordinates with a radial coordinate ##r## defined the way it is in Schwarzschild coordinates (such that the area of a 2-sphere at radial coordinate ##r## is ##4 \pi r^2##), those are the "static coordinates" described at that link.
 
That's great. Thanks!

Given:
\begin{equation}
\begin{split}
d\vec{s}^2&=\left(\frac{1}{1-\frac{\vec{r}_s}{\vec{r}}-\frac{\Lambda \vec{r}^2}{3}} \right) d\vec{r}^2 + \vec{r}^2 \left(d\theta^2 + \sin^2\theta d\varphi^2 \right) -\left(1 - \frac{\vec{r}_s}{\vec{r}}-\frac{\Lambda \vec{r}^2}{3} \right) dt^2
\end{split}
\end{equation}

Am I correct in the following, where ##\tilde{\infty}## denotes complex infinity?:
\begin{equation}
\begin{split}
\lim_{\vec{r}\to \infty} d\vec{s}&=\tilde{\infty}
\end{split}
\end{equation}

With a singularity at the transition between real and imaginary values for ##\vec{s}##.
 
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PeterDonis said:
It's the de Sitter metric; see here:

https://en.wikipedia.org/wiki/De_Sitter_space

If by "radial coordinates" you mean coordinates with a radial coordinate ##r## defined the way it is in Schwarzschild coordinates (such that the area of a 2-sphere at radial coordinate ##r## is ##4 \pi r^2##), those are the "static coordinates" described at that link.
Sure, this is what I quoted for ##m=0## (i.e., ##r_{\text{S}}=0##).
 
Given:
\begin{equation}
\begin{split}
d\vec{s}^2&=\left(\frac{1}{1-\frac{\vec{r}_s}{\vec{r}}-\frac{\Lambda \vec{r}^2}{3}} \right) d\vec{r}^2 + \vec{r}^2 \left(d\theta^2 + \sin^2\theta d\varphi^2 \right) -\left(1 - \frac{\vec{r}_s}{\vec{r}}-\frac{\Lambda \vec{r}^2}{3} \right) dt^2
\end{split}
\end{equation}

Am I right in understanding ##\Lambda## is negative such that ##\frac{\Lambda \vec{r}^2}{3}## is positive?