roineust said:
Harald,
Most of your last answer was even more hard for me to understand than the previous one, due to lack of knowledge on my side.
Dear Roi,
I assumed that you had read the introduction of Michelson's paper to which I gave the link earlier, and in which he makes the basic calculation to which I referred. Without that, much more elaboration would have been necessary.
Anyhow I noticed that there is a recurring theme in SR explanations, that has to do with light going one way and then (or as well) the other way back.
Please take a look at this diagram:
https://www.physicsforums.com/attachment.php?attachmentid=30765&d=1292890665
In this diagram, there is only light going one way as much as I understand.
My question is, if we know for sure that the 'crystal' (e.g. a precise enough clock) is dilated, e.g. one (or ten) vibrations (or ticks) are not the same in the moving apparatus and in the stationary apparatus, as well we know for sure that the electricity (e.g. light) in both apparatus travels at the same speed, then necessarily the exact same configuration that made light sources turn on together in the stationary apparatus, will not make them turn on together in the moving apparatus, therefore physical laws invariance would be incorrect.
I think this arrangement is simple enough for me to understand. Where did I get it wrong with this diagram?
Thanks,
Roi.
OK, I see there a push button connected to, in parallel:
1. a crystal and wires going to a light bulb,
2. a long wire ball and wires going to another light bulb
The wire ball causes the same time delay as the crystal.
To this would apply the relativistic Fresnel-Fizeau equation we mentioned just before. The electricity will be slightly "dragged" by the moving wire. But let's keep it simple and pretend that electricity propagates at c through the wire, unhindered by the wire (the wire causes a small delay plus drag when moving but we'll ignore all that here).
Now you put the whole system in motion. First of all, you claim that the time (as measured in your stationary system) for electricity to go through the wire is still the same. Instead you must calculate roughly like Michelson did!
Say your system moves to the
right while the electricity propagates to the left at speed c. The time through the wire will thus be reduced.
But we can leave out all that, for the wires are the same in both. We are left with comparing the wire ball and the crystal.
a. the crystal: yes it slows down, so the time delay will increase
b. the wire ball: difficult to calculate an unidentified wire ball. Let's make it orderly and turn it into a big zigzag - for example something like the MMX arm of my last post!
Now we are back to the basic Michelson calculation which you don't understand, which plus the Lorentz contraction term leads to the exact same time delay as that of the crystal...
OK then, here a quick sketch of that part of Michelson's calculation: the signal propagates from point 1 to the mirror and on to point 2, here the first leg is in counter speed to the system and on the return leg the signal is running in the same direction as the apparatus. The total trajectory in space is therefore less than length L on the first leg and more than length L on the return leg because the mirror and point 2 move to the right:
t1
|<---------------1 v-->
|---------------------->2
t2
For the calculation it's easier to take the relative speed of light and arm, as seen by you:
t1 = L/(c+v)
t2 = L/(c-v)
t1+t2 = T = [L(c-v)+L(c+v)] / [(c+v)(c-v)]
T = 2L * c /(c² - v²) = 2L/c * 1/(1 -v²/c²)
(For more explanation, see again his paper:
http://en.wikisource.org/wiki/On_the_Relative_Motion_of_the_Earth_and_the_Luminiferous_Ether )
However, according to Lorentz and Einstein one should also account for Lorentz contraction.
Summary:
In rest, T = 2L/c
In motion, according to Michelson, T = 2L/c * 1/(1 -v²/c²)
In motion, according to Lorentz, T = 2L/c * 1/SQRT(1 -v²/c²)
And the last is just the time dilation factor of your crystal.
Did that help?