Microcanonical ensemble generalized pressure

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SUMMARY

The discussion centers on the derivation of pressure in the microcanonical ensemble, specifically addressing the equation ##dW = \bar p dV##. The pressure is defined as ##\bar p = \frac{1}{Z} \sum_{r} e^{-\beta E_r} (-\frac{\partial E_r}{\partial V})##, where ##Z## is the partition function. The confusion arises regarding the use of the partial derivative ##\frac{\partial E_r}{\partial V}## while keeping entropy ##S## constant, which is clarified by referencing the Landau potential ##\Phi=-k_B T \ln Z## and its relation to internal energy ##U##. The discussion emphasizes the importance of understanding the natural variables involved in these thermodynamic potentials.

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This discussion is beneficial for physicists, particularly those specializing in statistical mechanics, thermodynamics, and anyone researching the properties of microcanonical and macrocanonical ensembles.

Mayan Fung
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In the discussion of the pressure in macrocanonical ensemble, I found in textbook that:
##dW = \bar p dV## (##dW## is in fact d_bar W, yet I can't type the bar)
The derivation goes like:
##\bar p = \frac{1}{Z} \sum_{r} e^{-\beta E_r} (-\frac{\partial E_r}{\partial V}) = ... = \frac{1}{\beta} \frac{\partial lnZ}{\partial V}##

However, ## E = TdS - pdV## and in macrocanonical ensemble, we have ##T,V,N## as variables. That means ##\frac{\partial E_r}{\partial V} = (\frac{\partial E_r}{\partial V})_{T,N}## but not keeping entropy ##S## constant.

I am confused about why we can use ##\frac{\partial E_r}{\partial V}## in the above derivation
 
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Hi,

Chan Pok Fung said:
That means but not keeping entropy constant.

please, crosscheck that the partial derivative is for S and N constant

https://de.wikipedia.org/wiki/Mikrokanonisches_Ensemble#Druck
(sorry, it was the only wikipedia article with the pressure definition as partial derivative)

Regards,
ORF
 
It's just using different potentials. It turns out that ##\Phi=-k_B T \ln Z## is the Landau potential with natural variables ##S##, ##T##, and ##\mu##. The relation with the internal energy ##U## is
$$\Phi=U-TS-\mu N.$$

For details see

https://itp.uni-frankfurt.de/~hees/publ/off-eq-qft.pdf
Sect. 2.1.4

Note that in this manuscript I use natural units with ##k_B=1## and in the relativistic context instead of a conserved particle number I use some conserved charge ##Q## (like electric chrage) to introduce a corresponding chemical potential.
 
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