Minimum compression of a spring.

AI Thread Summary
To determine the minimum compression of a spring needed for a toy car to complete a vertical loop, calculations were performed using the car's mass of 0.043 kg and a spring constant of 92 N/m. The required velocity at the top of the loop was derived from centripetal acceleration, leading to a kinetic energy calculation of 0.03225 J. The potential energy at the top of the loop was initially miscalculated but corrected to 0.129 J. The total energy equation was set up, leading to the conclusion that the minimum spring compression is approximately 0.0592 m. The calculations were confirmed to be correct after addressing the potential energy error.
college boy19
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A toy car with mass 0.043 kg is propelled by a spring with spring constant 92 N/m onto a track. The track contains a vertical loop of radius 0.15 m. Ignore any losses due to friction and use g = 10 m/s2. What is the minimum compression of the spring necessary for the car to complete the loop without leaving the track?

acceleration = velocity^2/radius= 10(0.15)= velocity^2
so v^2= 1.5

Then I use V to get KE = 1/2mv^2
KE= 1/2(0.043)(1.5)
KE= 0.03225

Add PE to the top of the loop PE = mgh
PE= (0.043)(10)(0.3)
PE=.0129

so then the Total E = PE + KE

TE = 1/2k x^2
PE+ KE= 1/2k x^2
.0129+ 0.03225= 1/2 (92) x^2
0.16125= 1/2 (92) x^2
0.3225 = 92x^2
0.003505 = x^2
x = minimum compression = 0.0592

Did i do everything correctly or is there a mistake somewhere?
 
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college boy19 said:
Add PE to the top of the loop PE = mgh
PE= (0.043)(10)(0.3)
PE=.0129 math error; PE = 0.129[/color]


Did i do everything correctly or is there a mistake somewhere?
Correct that simple math error and everything else looks OK.
 
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