Minimum energy of electron bound in nucleus

AI Thread Summary
To estimate the minimum energy of an electron confined to a nucleus of radius 4 femtometres, the uncertainty principle is applied, specifically ΔxΔp_x=h/4π. The discussion highlights that the electron's rest energy is negligible compared to its kinetic energy, leading to the use of the energy equation E=pc. A point of confusion arises regarding the use of Δp_x/2 in calculations instead of Δp_x, with a suggestion that this represents a momentum uncertainty. The rationale behind this approach and its equivalence to momentum uncertainty is debated, indicating a need for clarification on the application of the uncertainty principle in this context. Understanding these concepts is crucial for accurately estimating the electron's minimum energy.
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Homework Statement



An electron is confined to a nucleus of radius 4 femtometres. Estimate its minimum energy.

Homework Equations



ΔxΔp_x=h/4\pi
E^2=p^2c^2 + m^2c^4

As the electron's rest energy will be much less than it's kinetic energy,

E=pc

The Attempt at a Solution



So I understand that I'm supposed to use the uncertainty principle to find the average momentum, and then plug it into the energy equation. What I don't understand is that the solutions use Δpx/2 instead of just Δpx. Why is this?
 
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I think that Δpx/2 in both directions gives a difference of Δpx, which is "somehow" equivalent to a momentum uncertainty.
Using Δpx is probably fine, too.
 
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