Minimum motor power for a mechanical horizontal sieving machine

AI Thread Summary
The discussion focuses on calculating the minimum motor power required for a mechanical horizontal sieving machine. Key calculations include determining acceleration, friction force, crank force, total force, and torque, leading to a final motor power requirement of 50 watts. The motor must accelerate the mass of the screen and powder while overcoming friction, necessitating a specific horizontal force. Additionally, the crank mechanism's torque requirements at various angles are emphasized for effective operation. The user seeks validation of their calculations and methodology.
khodournajem
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Homework Statement
I'm making a small project (horizontal sieving machine)
i will use the crank slide mechanism , the doctor want from me to calculate the input power of the dc motor and the output power to calculate the efficiency of the system.
so i test the maximum load which is 10 kg equally distributed on a frame of 6 bearings of friction coefficient 0.3,
the minimum displacement of the net frame to begin sieving is 5 cm per 1 second which is 0.05/s meters,
so the crank radius will be 2.5 cm (0.025) that gives a 60 rpm and i am using a 10 cm connecting rode. so this is my critical issue.
is i'm thinking right ?
how can i calculate the power?
do i have to calculate the force of the crank ?
how can i calculate the output power if my result is correct.
please help
Relevant Equations
𝐹=μN

𝐹𝑐𝑟𝑎𝑛𝑘=ma

𝜏=F×d

P=τ×w
r = 2.5
l=10 cm
angle = 0 (maximum connecting rode elongation)
w = 0.5 (30 rpm)
n=10/2.5 = 4
so the acceleration is 1.5×0.5×0.5(1 + 1/4 ) = 0.4 m/s

friction force = 10*9.81*0.3 = 29.4 Newton.

Crank force is the mass of the object into acceleration.
So crank force = 10 × 0.4 = 4 Newton
Therefore total force will be: 29.4 + 4 =33.4 Newton.

Torque is the total force into the distance.
So torque = 33.4 × 0.05 = 1.67 N.m.

Finally motor power is the torque into the angular speed in minute.
Power = 1.67 × 30 = 50 watts.here is a approx picture (in my project the motor and the connecting rode and the frame is horizontally placed)
 

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Welcome, khodournajem!

The motor will need to accelerate the mass of the screen and powder from V=0 to V=max at half of the stroke in certain period of time, while overcoming friction.
That will demand a horizontal force that can be calculated.
The crank mechanism will require the greater torque at certain angle position to provide that horizontal force.
Then, you can add some safety factor regarding the needed torque at the required rpm of your motor for its selection.

 
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Likes khodournajem
thank you lnewqban for your time ,

i know these informations , i want to know if my calculations, used equations and last result are correct .
regards.
 

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