Minimum MSE estimation derivation

EmmaSaunders1
Messages
45
Reaction score
0
Hello,

Would anyone be-able to recommend a good, easy to read article which outlines MMSE and its derivation. Specifically I am having trouble finding this term


<br /> + \int x&#039;xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2<br />

from

<br /> E({\left | \left | X-z \right | \right |}^2|Y=y)<br /> =\int (x-z)&#039;(x-z)P(x|y)dx\\<br /> =[z&#039;-\int x&#039;P(x|y)dx][z-\int xP(x|y)dx] + \int x&#039;xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2<br />

Thank you
 
Physics news on Phys.org
Shouldnt the term just be zero - I can't understand it's presence - are there any conditions in which it is not zero??
 
For anyone who is interested - the last term

<br /> + \int x&#039;xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2<br />

is necessary to account for the difference between E(x^2) and [E(x)]^2. When Z = E[x|Y=y] the term

<br /> E({\left | \left | X-z \right | \right |}^2|Y=y)<br />

Is a minimum and reduces to

<br /> + \int x&#039;xP(x|y)dx-\left \| \int xP(x|y)dx \right \|^2 = <br />

Then

<br /> E({\left | \left | X \right | \right |}^2|Y=y)-E(X|Y=y)^2\\<br /> =E({\left | \left | X \right | \right |}^2|Y=y)-{\left | \left | \hat{X} \right | \right |}^2<br />

which is the average mean square error
 
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Back
Top