Minkowski metric tensor computation

Advent
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Hi, I'm having problem with understanding tensors and the Einsteins summation convention, so I decided to start doing explicit calculations, and I'm doing it in the wrong way. Hope someone could help me to clarify the concepts.

In flat spacetime we have \eta with the signature (-+++). Under some coordinate change, say x_{\mu} \rightarrow x_{\overline{\mu}}, then the metric changes as g_{ \overline{\mu} \overline{\nu}}=\frac{ \partial x^{\rho}}{ \partial x_{\overline{\mu}}} \frac{ \partial x^{\sigma}}{ \partial x_{\overline{\nu}}}g_{ \overline{\rho} \overline{\sigma}}. So, If I change the coordinate system from Cartesian (t,x,y,z) to spherical (t,r, \theta, \varphi) with the following equations

x = r \cos(\varphi) \cos (\theta), y = r \cos(\varphi) \sin (\theta), z = r \sin(\varphi), t = t. The four non-zero componentes of the metric \eta in spherical coordinates should be:

g_{11} = (\frac{ \partial t }{ \partial t })^2 g_{1'1'}=-1


g_{22} =(\frac{ \partial x }{ \partial r })^2 g_{2'2'}=\cos^2(\varphi) \cos^2 (\theta)


g_{33} =(\frac{ \partial y }{ \partial \theta })^2 g_{3'3'}=r^2 \cos^2(\varphi) \cos^2 (\theta)


g_{44} =(\frac{ \partial z }{ \partial \varphi })^2 g_{4'4'}=r^2 \cos^2(\varphi)

And finally, the line element ds^2=g_{\mu \nu}dx^{\mu}dx^{\nu}=dt^2+\cos^2(\varphi) \cos^2 dr^2+ r^2 \cos^2(\varphi) \cos^2 d^2 \theta + r^2 \cos^2(\varphi) d^2 \varphi which is incorrect.

Thanks for your time, any help will be appreciated.
 
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Did you sum over the repeated indices in the change of coordinates formula (summation convention)?
 
atyy said:
Did you sum over the repeated indices in the change of coordinates formula (summation convention)?

I think I did, in fact it explains the square of the derivatives.
 
I'm not sure about this, but I think in grr you should have terms like (dt/dr)^2.gtt+(dx/dr)^2.gxx+(dy/dr)^2.gyy+(dz/dr)^2+(dt/dr)(dx/dr)gtr + ...

where in your formula I've taken u=r,v=r and rho and sigma must be summed over all combinations of rho=t,x,y,x and sigma=t,x,y,z
 
atyy said:
I'm not sure about this, but I think in grr you should have terms like (dt/dr)^2.gtt+(dx/dr)^2.gxx+(dy/dr)^2.gyy+(dz/dr)^2+(dt/dr)(dx/dr)gtr + ...

Thanks for your posts.

I think now I understand your point. Do you mean that, in the equation of the line element should be 4*4=16 summands instead of only four, by varying the ro and sigma indices between all their range?
 
Ok, just answered too fast!

Then this was my error, thank you so much!
 
Advent said:
Ok, just answered too fast!

Then this was my error, thank you so much!

Wow, you sure compute fast! Good to know - I wasn't sure about this.
 
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