Mixing Problem with Constant Coefficient Differential Equation

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Homework Help Overview

The problem involves a tank containing pure water into which a sugar solution is introduced. Participants are tasked with determining the initial amount of sugar, the amount after a certain time, and the concentration after 72 minutes, using a constant coefficient differential equation approach.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formulation of the differential equation and the rates of sugar entering and leaving the tank. There is uncertainty about the separation of variables and the correct method to solve the equation, with some questioning the concept of "constant coefficient."

Discussion Status

Some participants affirm that the original poster is on the right track with their formulation of the differential equation. Guidance is provided regarding different methods to approach the problem, including the suggestion to use the constant coefficient method first.

Contextual Notes

Participants express confusion about the terminology and methods related to constant coefficient differential equations, indicating a potential gap in prior knowledge or exposure to the topic.

CollegeStudent
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Homework Statement



A tank contains 1160 L of pure water. A solution that contains 0.03 kg of sugar per liter enters a tank at the rate 7 L/min The solution is mixed and drains from the tank at the same rate.

a.) How much sugar is in the tank initially?
b.) Find the amount of sugar in the tank after t minutes.
c.) Find the concentration of sugar in the solution in the tank after 72 minutes.

Homework Equations


The Attempt at a Solution



I made s(t) be the amount of salt at time 't'

ds/dt = rate in - rate out

Well the rate in would be the concentration times the rate... so

ds/dt = (.03kg)(7L/min) - (s/1160)(7L/min)

ds/dt = .21 - (7s/1160)

Kind of get confused from there...I figure I'll have to get the 's' on one side right? separable?Am I even on the right track here? Just starting out in the class.
 
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CollegeStudent said:

Homework Statement



A tank contains 1160 L of pure water. A solution that contains 0.03 kg of sugar per liter enters a tank at the rate 7 L/min The solution is mixed and drains from the tank at the same rate.

a.) How much sugar is in the tank initially?
b.) Find the amount of sugar in the tank after t minutes.
c.) Find the concentration of sugar in the solution in the tank after 72 minutes.

Homework Equations





The Attempt at a Solution



I made s(t) be the amount of salt at time 't'

ds/dt = rate in - rate out

Well the rate in would be the concentration times the rate... so

ds/dt = (.03kg)(7L/min) - (s/1160)(7L/min)

ds/dt = .21 - (7s/1160)

Kind of get confused from there...I figure I'll have to get the 's' on one side right? separable?


Am I even on the right track here? Just starting out in the class.

Yes, you are on the right track. So far so good.

If you call ##a = \frac 7 {1160}## your equation can be rewritten$$
\frac{ds}{dt} +as = .21$$It is constant coefficient, linear, and separable, so any of these methods would work. I would suggest the constant coefficient method first, linear (integrating factor) second, and separation of variables last in order of preference.
 
Constant coefficient? I wouldn't just integrate here? I'm looking all over the web for an explanation of "constant coefficient" but not seeing too much
 
CollegeStudent said:
Constant coefficient? I wouldn't just integrate here? I'm looking all over the web for an explanation of "constant coefficient" but not seeing too much

That's "constant coefficient differential equation". If you haven't studied those yet use the integrating factor method for first order linear DE's.
 

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