Mixture problem 2 - linear equation

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Discussion Overview

The discussion revolves around a mixture problem involving the calculation of percentages of components in clay and coal, specifically focusing on silica and carbon content on a dry and wet basis. The participants explore the implications of drying on the composition of these materials.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant claims that if the clay is water-free, it would be 100% silica, questioning the correctness of this assertion.
  • Another participant clarifies that before drying, the clay consists of 45% silica and 10% water, implying that there are other substances present, totaling 55% of the clay's weight.
  • A hypothetical scenario is proposed where wet clay weighs 100 kg, leading to calculations of the weights of silica, water, and other substances.
  • One participant suggests that after drying, the mass of silica remains the same, while another counters that the total mass after evaporation is 90 kg, leading to a recalculation of the percentage of silica in the new total mass.
  • For the coal problem, participants discuss the percentage of carbon on a wet basis, with one participant expressing uncertainty and seeking assistance.

Areas of Agreement / Disagreement

Participants express differing views on the percentage of silica after drying, with some asserting it remains 45% while others argue it must be recalculated based on the new total mass. The discussion regarding the coal problem also shows uncertainty and a lack of consensus on the correct approach.

Contextual Notes

Participants rely on hypothetical weights for calculations, which may not account for all variables in real-world scenarios. The assumptions made about the composition of the clay and coal are not universally agreed upon.

paulmdrdo1
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1. A clay contains 45% silica and 10% water. Determine the percentage of silica in the clay on a dry (water-free) basis. All percentages are by weight.

my answer is 100% silica. because if the clay is water free the clay is 100% silica. is this correct?

2. A coal contains 2.4% water. After drying, the moisture-free residue contains 71.0% carbon.
Determine the percentage of carbon on the “wet basis.” All percentages are by weight.

for this I have no idea. please give me some assistance here. thanks!
 
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paulmdrdo said:
1. A clay contains 45% silica and 10% water. Determine the percentage of silica in the clay on a dry (water-free) basis. All percentages are by weight.

my answer is 100% silica. because if the clay is water free the clay is 100% silica. is this correct?
But before drying silica and water constituted only 45% + 10% = 55% of clay. The rest 45% were other substances. Do you think they evaporated during drying?

Suppose wet clay weighs 100 kg. Then silica weighs 45 kg, water weighs 10 kg and other substances also weigh 45 kg. After drying, water evaporates, but silica and other substances remain. What share of the new total volume does silica make up?

paulmdrdo said:
2. A coal contains 2.4% water. After drying, the moisture-free residue contains 71.0% carbon.
Determine the percentage of carbon on the “wet basis.” All percentages are by weight.

for this I have no idea. please give me some assistance here. thanks!
Suppose the orginal coal weighs 100 kg. Then water weighs 2.4 kg, so dry matter, including carbon, weighs 97.6 kg. Of that dry matter carbon makes up 71%. Find the mass of carbon and divide by the original mass, i.e., 100 kg.
 
the silica would still be 45%. Am I correct?

please I need a quick response for this. thanks!
 
Evgeny.Makarov said:
Suppose wet clay weighs 100 kg. Then silica weighs 45 kg, water weighs 10 kg and other substances also weigh 45 kg. After drying, water evaporates, but silica and other substances remain. What share of the new total volume does silica make up?

paulmdrdo said:
the silica would still be 45%. Am I correct?
No. The total mass (sorry, I mistakenly said volume before) after evaporation is: 45 kg silica + 45 kg other substances = 90 kg. Silica makes up 45 / 90 = 0.5 of that new total mass.
 

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