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**with**the effects of gravity and air resistance taken into account or the velocity purely from the motor (without any air resistance or gravity taken into account)?

Your help is appreciated, thanks.

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The drag equation is a mathematical model that calculates the force exerted by the air on an object in motion. The air resistance equation is a mathematical model that calculates the force exerted by the air on a surface (like a rocket) in motion.

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Your help is appreciated, thanks.

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https://en.wikipedia.org/wiki/Drag_equationAndy24 said:but am stuck as to which value for 'v' to use?

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That's reminds me that I forgot to add that it is the velocityA.T. said:

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DrClaude said:That's reminds me that I forgot to add that it is the velocitywith respect to the surrounding air.

Thanks for your response.. I understand now. I actually calculated the velocity based on some ground testing (where I found out the impulse of the motor) and was hoping to incorporate drag.. This may give you context: https://www.physicsforums.com/threads/coefficient-of-drag-on-a-model-rocket.871810/

Thanks for your help though, I think I might just leave incorporating drag into my calculations as I have 2 unknowns- the force due to drag as well as the actual velocity. Thanks again,

Andrea

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In this context, the terms "drag" and "air resistance" are synonymous.Andy24 said:Hello! I am predicting the peak altitude of a model rocket based on some ground tests. I know that Total Force on the rocket=Thrust-mg-kv^2 but am stuck as to which value for 'v' to use? Is it the velocity of the rocketwiththe effects of gravity and air resistance taken into account or the velocity purely from the motor (without any air resistance or gravity taken into account)?

The 'v' in the drag equation represents the velocity of the object. This means that as the velocity of the object increases, the drag force acting on it will also increase.

The 'v' in the drag equation is squared, meaning that it has a significant impact on the overall drag force. This means that as the velocity of the object increases, the drag force will increase exponentially.

Yes, there is a limit to how much the 'v' can affect the drag force. As the velocity of the object approaches the speed of sound, the drag force will reach its maximum value and will not increase any further.

The 'k' constant in the drag equation represents the drag coefficient, which is unique to each object and determines how much drag force it experiences at a given velocity. A higher 'k' value means that the object experiences more drag force at a given velocity.

No, the 'v' in the drag equation cannot be negative. Velocity is a vector quantity and cannot have a negative value. The direction of the velocity may change, but the magnitude (or speed) will always be positive.

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