- #1
aahas3
- 3
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Part B the indeterminate question.
Divided the question into 3 Parts
Moment due to UDL
M = 2x4x2 = 16 Kn
EItab = Marea . Xa = 0
16 x 4 x 1/3 x( 1/4 x 4) ( parabola)
Due to 5kn Load
Split it up to on rectangular and on triangular load as the 5kn load goes to 6 m and analysing for 4 m to b.
M = 5 x 6 = 30
30 = 6
x = 4 therefore x = 20
=4x20x2 + 4 x 10 x 1/2 x ( 1/3 x 4)
=
Due to redundant reaction By
M = By x 4 = 4by
= - by4 x 4 x 1/2 x (1/3 x 4)
This gives a By of 19.49 instead of 11.125 specified in the answer sheet if added together as deflection = 0
Divided the question into 3 Parts
Moment due to UDL
M = 2x4x2 = 16 Kn
EItab = Marea . Xa = 0
16 x 4 x 1/3 x( 1/4 x 4) ( parabola)
Due to 5kn Load
Split it up to on rectangular and on triangular load as the 5kn load goes to 6 m and analysing for 4 m to b.
M = 5 x 6 = 30
30 = 6
x = 4 therefore x = 20
=4x20x2 + 4 x 10 x 1/2 x ( 1/3 x 4)
=
Due to redundant reaction By
M = By x 4 = 4by
= - by4 x 4 x 1/2 x (1/3 x 4)
This gives a By of 19.49 instead of 11.125 specified in the answer sheet if added together as deflection = 0