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**1. Homework Statement**

Consider a rod length L and mass m which is pivoted at one end. An object with mass m attached to the free end of the rod. g=9.8 m/s^2. Note: Contrary to the diagram shown, consider the mass at the end of the rod to be a point particle.

Basically it looks like a rod pivoted at a point on the origin, and 23 degrees below the x-axis.

1) determine the moment of Inertia, I, of the system with respect to the pivot joint.

I tried doing the sum of the moments about the pivot joint, I= m(L)^2/12 for the rod plus I= m (L)^2 of the point mass and got (13/12)*m*(L)^2 but it was wrong.

2) Determine the position of the center of mass from the pivot point, i.e., find C.

I used xcm= (mL+mL)/(m+m) and got C=L. Can someone tell me if i did that correctly?

**3. The Attempt at a Solution**