Moment of Inertia for 2D Rectangle: Does it Depend on Both Sides?

AI Thread Summary
The moment of inertia for a two-dimensional rectangle with sides a and b, when the axis is parallel to one of its sides and passes through its center of mass, is not given by the formula (1/12)M(a²+b²). Instead, if the axis is parallel to side a, the moment of inertia is (Ma²)/12, indicating that it primarily depends on the dimension parallel to the axis. The discussion highlights that while the formula may seem counterintuitive, it accurately reflects the distribution of mass relative to the chosen axis. The moment of inertia does not depend on the other side of the rectangle in this configuration. Understanding this concept is crucial for correctly applying the principles of rotational dynamics.
peripatein
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Hi,

Homework Statement


Will the moment of inertia of a two dimensional rectangle (with sides a, b) whose axis is parallel to one of its sides and passes through its center of mass, be (1/12)M(a2+b2)?


Homework Equations





The Attempt at a Solution

 
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peripatein said:

Homework Statement


Will the moment of inertia of a two dimensional rectangle (with sides a, b) whose axis is parallel to one of its sides and passes through its center of mass, be (1/12)M(a2+b2)?
No. If the axis is, say, the y axis, think of the lamina as a set of parallel thin strips in the x direction. They'll all have the same moment. I think the formula you quoted would be right for an axis perpendicular to the lamina.
 
But then wouldn't I be getting a moment of inertia equal to (Ma^2)/12 (supposing axis is parallel to a)?
 
And what's wrong with that?
 
It's not that something's wrong with that, simply that it seemed a bit strange it would not depend on the other side too.
 
peripatein said:
It's not that something's wrong with that, simply that it seemed a bit strange it would not depend on the other side too.
That's why I said to think of it as parallel strips across the axis. Adding more only increases the moment in proportion to the mass.
 
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