Moment of Inertia of Disk at any point

AI Thread Summary
The moment of inertia of a disc at its center of mass is given by the formula 0.5mr^2. For points other than the center of mass, the parallel axis theorem can be applied, which states that the moment of inertia about a parallel axis is calculated as I = I_cm + md^2, where I_cm is the moment of inertia about the center of mass, m is the mass, and d is the distance from the center of mass to the new axis. The discussion also touches on the applicability of this theorem to 3D shapes. The conversation concludes with a reminder of the parallel axis theorem's relevance.
TheDestroyer
Messages
401
Reaction score
1
As we know the moment of Inertia of a disc in the center of mass equals 0.5mr^2

My Simple question is: what is the moment of inertia of the disc at any other point? as I know there is a formula that supports the distance from the center of mass,

and is there a relation for 3D shapes?

Thanks
 
Physics news on Phys.org
Do you know the parallel axis theorem?

The moment of inertia for an object rotating about an axis that does not pass through its centre of mass, but which is parallel to it, is

mr^2 + (moment of inertia about an axis through the centre of mass and parallel to the other axis)

The r is the distance from the axis to the centre of mass.
 
Thank you, I know that law but this was 3 years ago, Thank you for reminding me, This post is closed!
 
Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top