Moment of Inertia: Proving Mass, Side & Axis | 1/12 md²

AI Thread Summary
To prove that the moment of inertia of a uniform square of mass m and side d about an axis through its center, parallel to a side, is 1/12 md², one must use the definition of moment of inertia, which involves integration. The discussion emphasizes the importance of setting up the correct integral for the calculation. Participants encourage the user to write out the integral and attempt the integration process to derive the proof. Clarification on the procedure is provided, indicating that the outcome of the integration will serve as the proof needed. Engaging in this methodical approach will help solidify understanding of the concept.
Chadi B Ghaith
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I need help to prove that the moment of inertia of a uniform square of mass m and side d about an axis through its centre, parallel to a side is 1/12 md²
 
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Chadi B Ghaith said:
I need help to prove that the moment of inertia of a uniform square of mass m and side d about an axis through its centre, parallel to a side is 1/12 md²
OK, what kind of help ? You know the definition of moment of inertia ? It amounts to an integration; does that pose a problem ? Write it out and we'll help you further.
 
BvU said:
OK, what kind of help ? You know the definition of moment of inertia ? It amounts to an integration; does that pose a problem ? Write it out and we'll help you further.
Hi,
Yes I know the definition of inertia. What I am asking is how to prove the above statement. I am bit confuse in procedure.
 
Good you know it. Write down the integral and attempt to do the integration in your next post. The outcome of your calculation is your 'proof'.
 

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