Moments - How are they actually calculated?

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Discussion Overview

The discussion revolves around the calculation of moments in physics, specifically whether moments are determined by the total force or the perpendicular component of the force relative to an axis. The context includes conceptual clarification and mathematical reasoning related to the application of forces on objects.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Main Points Raised

  • One participant questions whether moments are calculated using the total force or just the perpendicular component of the force to the axis.
  • Another participant asserts that moments should be calculated using the perpendicular component, stating that the parallel component does not produce any moment.
  • A third participant provides a mathematical expression for moments, indicating that the magnitude involves the sine of the angle between the position vector and the force vector, reinforcing the idea that it relates to the perpendicular component of the force.

Areas of Agreement / Disagreement

There appears to be general agreement among participants that moments are calculated using the perpendicular component of the force, though the initial question reflects some uncertainty about the correct approach.

Contextual Notes

The discussion does not address potential limitations or assumptions regarding the definitions of force components or the specific conditions under which these calculations apply.

012anonymousx
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Moments -- How are they actually calculated?

Hello, I have a question.

Is the moment calculated:

Force times the distance or

Force's perpendicular component (to axis) times the distance.

For example, let's say I have a stick.

Pulling on it is not moment.

So if I push at the stick to an angle, the way I calculate the force that the other side is applying is by taking the perpendicular component of my Fa and multiplying it by the distance.

Is that correct?
 
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Yes, when you are calculating moments, you would use the perpendicular component. The parallel component will not produce any moment as the perpendicular distance is zero.
 
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Mathematically, a moment is ##\vec{l} = \vec{r} \times \vec{f}##. The magnitude comes out as ##l = rf\sin\theta##, where ##\theta## is the angle between the position vector and the force vector. This is equivalent to saying that it is the perpendicular component of the force.
 
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Thank you!
 

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