Momentum and Impulse separation question

Thread starter thepagal
Start date Apr 14, 2013
Tags

Impulse Momentum Separation

AI Thread Summary

To find the third velocity of three equal masses that break apart from rest, conservation of momentum principles must be applied. Since the system starts at rest, the total initial momentum is zero, meaning the vector sum of the velocities of the three masses must also equal zero after the break. The discussion indicates a need for clarity on how to set up the equations based on the given velocities of the first two masses. Understanding the direction and magnitude of these velocities is crucial for solving for the third velocity. Applying these concepts will lead to the correct solution.

Apr 14, 2013

thepagal

Homework Statement

3 equal masses at rest break apart as shown. Find the 3rd velocity

Homework Equations

http://i168.photobucket.com/albums/u175/kingzer2/Photo2013-04-14073115PM_zps0ee829e4.jpg?t=1365985942

The Attempt at a Solution

I really have no idea how to do this :( sorry

Last edited by a moderator: May 6, 2017

Physics news on Phys.org

Apr 14, 2013

barryj

Think conservation of momentum

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »