That's correct. In fact, that is precisely what Newton's second law of motion says. An external force is needed to change the momentum, and the rate at which the momentum changes is proportional to the force. This means there is some constant of proportionality that relates forces and changes in momentum. In mathematical form,
[tex]\vec F = k \frac {d\vec p}{dt}[/tex]
where [itex]\vec F[/itex] and [itex]\vec p[/itex] are the force and momentum vectors respectively and [itex]k[/itex] is some constant of proportionality. In the metric system of units, the units of mass, length, and time are intentionally defined to make that constant of proportionality equal to one.
In the case that an object's mass is constant, change in momentum is proportional to change in velocity, and the constant of proportionality is the object's mass. Thus for a object with constant mass, Newton's second law can be expressed as
[tex]\vec F = m\frac {d\vec v}{dt} = m\vec a[/tex]
This is the form of Newton second law with which you have probably familiar.
Note that I dropped the constant of proportionality here -- I am assuming a system of units such as the metric system where the constant of proportionality is one. The more general form is
[tex]\vec F = k m\vec a[/tex]
and this is the form you need to use if you measure force in pounds-force, mass in pounds-mass, and acceleration in feet/second/second (in which case [itex]k=1/32.1740486\,\text{lbf}\;\text{s}^2/\text{ft}/\text{lbm}[/itex]).