Momentum if Velocity is Doubled

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If a car has a momentum of 25,876 units, doubling its velocity results in a new momentum of 51,752 units. The calculation is based on the formula for momentum, which is mass multiplied by velocity. The initial momentum equation is set as 25,876 = m x v, and when velocity is doubled, it becomes 51,752 = m x 2v. The solution confirms that the new momentum is indeed correct. The answer was submitted successfully.
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Homework Statement


A car possesses 25,876 units of momentum. What would the car's new momentum be if the velocity is doubled?


Homework Equations


momentum = mass x velocity


The Attempt at a Solution


momentum = mass x velocity
25,876 = m x v
51,752 = m x 2v

The new car's momentum would be 51,752 units.

Am I right?
 
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Yes, you are correct.
 
Doc Al said:
Yes, you are correct.

Thank you! I submitted the answer, and I was indeed correct. :smile:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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